3 years ago

Solve allgebraically for x: log base 27 (2x-1)=4/3

1 answer:

3 0

$log_{27}(2x-1)=\frac{4}{3};\ \ \ \ D:2x-1 > 0\to x > \frac{1}{2}\\\\log_{27}(2x-1)=log_{27}27^\frac{4}{3}\iff 2x-1=27^\frac{4}{3}\\\\2x-1=\left(\sqrt[3]{27}\right)^4\\\\2x-1=3^4\\\\2x-1=81\ \ \ /+1\\\\2x=82\ \ \ \ /:2\\\\x=41\in D$

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How do you figure this out

Ipatiy [6.2K]

$4 \times 8 = {32}^{2} \\ 3 \times 3 = {9 }^{2} \\ {32 + 9 = 41}^{2}$

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3 years ago

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almond37 [142]

Answer:

The correct answer is E.) Human resistance to change

I hope I helped! ^-^

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3 years ago

During a snowy day, it snowed lightly for a while, stopped for a while, snowed heavily, and then stopped. Which graph represents

kenny6666 [7]

The answer to your question is this graph (see attached).

Put the time portion on the x-axis and the snowfall portion on the y-axis. It snowed lightly for a while meaning it took some time for the snow to fall. From zero, move the graph a little going to x-axis (to the right). Then it stopped, giving the graph a gap (just maintain a short horizontal line) then snowed heavily, meaning, the snowfall increases then it stops (move the graph to the x-axis a little higher then another short horizontal line). Hope this helps you.