3/7 is the answer for this problem
Answer:
Karen
Step-by-step explanation:
Since neither 3/8 or 2/5 can be simplified further, you need to multiply them by the LCM to get the same denominator.
The LCM of 5 and 8 is 40.
Multiply 3/8 by 5 ( both numerator and denominator)(turns into 15/40 )
Multiply 2/5 by 8 ( both numerator and denominator)(turns into 16/40)
Now that they have the same denominator, we can see which one is closest to a whole mile.
16/40 is greater than 15/40, so Karen rode farther.
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Greetings!</h2>
Answer:
Horseback riding costs $30 and parasailing costs $51, so B.
Step-by-step explanation:
This is answered by using simultaneous equations, let x be parasailing and y be horseback riding.
3y + 2x = 192
2y + 3x = 213
Multiply each equation by the number in front of the y of the other equation:
2 x (3y + 2x = 192)
3 x (2y + 3x = 213)
Which results in:
6y + 4x = 384
6y + 9x = 639
Simply minus the two equations to get rid of the y:
6y - 6y = 0
4x - 9x = -5x
384 - 639 = -255
The negatives cancel out which give a result:
5x = 255
x =
x = 51
So parasailing costs $51
Now you can simply plug this value into one of the equations:
3y + (2 x 51) = 192
192 - 102 = 3y
90 = 3y
y =
y = 30
So horseback riding costs $30!
Hope this helps.
Answer:
1. x = -37 - 7y
2. x = 7+3y/4
Volume of a cone = π r² h/3
I envisioned a cone inside a cube. I only identified the necessary value to compute for the exact volume of the largest cone.
Edges of the cube is 10 inches. When the circle part of the cone is placed in the circle, the diameter would be 10 inches also. I divided it by 2 to get the value of the radius, resulting to 5 inches.
The height of the cone is also the height of the cube. Thus, it is 10 inches.
Volume of the cone = 3.14 * (5in)² * 10in/3
V = 3.14 * 25in² * 3.33 in
V = 261.405 in³ or 261.41 in³ VOLUME OF THE LARGEST CONE THAT CAN FIT IN A 10 INCH CUBE