All categories

3 years ago

What is the range of y =5/2(x-2)² - 4

Mathematics

1 answer:

blagie [28]3 years ago

7 0

Answer:

vertex:(2,-4)

Focus:(2,- $\frac{39}{10}$ )

Axis of symmetry :x=2

Directrixt: y=- $\frac{41}{10}$

Step-by-step explanation:

You might be interested in

Help please i know its alot but i am in danger of failing for the year if i fail this test :(

Lena [83]

Answer:

(20.) D is the correct answer

(19.) A is correct

(18.) A is correct

(17.) D is correct

(15.) A is correct

Step-by-step explanation:

hope this helps u ;)

3 0

2 years ago

In your notebook, set up the following addition using a vertical format and find the sum of the given polynomials.

Tasya [4]

The Correct Answer is "C"

5m^2 - 5mn +4n^2

5 0

2 years ago

Read 2 more answers

Given the function f(x)=2x-1 Evaluate: a) 2f(x) b) f(2x)

Dmitrij [34]

Answer:

a) 2f(x) = 4x - 2

b) f(2x) = 4x - 1

Explanation:

Given function:

f(x) = 2x - 1

a) 2f(x)

2f(x) = 2(2x - 1)

= 4x - 2

b) f(2x)

f(2x) = 2(2x) - 1

= 4x - 1

3 0

1 year ago

Plz help me out with this

nadya68 [22]

Given,

HK is the perpendicular bisector of GJ. So, GK = KJ.
GK = 2x + 10
KJ = 3x - 15

_______________

Find KJ .

_______________

First find the value of x

$\sf \: GK \: = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x = - 15 - 10 \\ \sf - x = - 25 \\ \sf \: - > \boxed{\bf \: x = 25}$

Now, find the value of KJ.

$\sf3x - 15 \\ \sf= 3(25) - 15 \\ \sf=7 5 - 15 \\ = \boxed{\bf \: 60}$

-> The value of KJ is 60.

_______________

Hope it helps.

RainbowSalt2222

6 0

2 years ago

Read 2 more answers

A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43

Umnica [9.8K]

Answer:

a) $z = 1.645$

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$ . This is the critical value, the answer for a).

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015$

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0

3 years ago