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WARRIOR [948]
4 years ago
9

Someone help with this please! Big points!

Mathematics
2 answers:
Marianna [84]4 years ago
4 0

I think A. is correct

Nat2105 [25]4 years ago
3 0

5\sqrt{72} =5\sqrt{36\cdot2}=5\sqrt{6^{2}\cdot2}=5 \cdot6\sqrt{2}   =30\sqrt{2}

Answer A.

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Write a polynomial with rational coefficients having roots 3,3+i and 3-i
Elena L [17]
Part 1: If the roots of a polynomial are a, b, and c, then the factors can be written in the form (x - a), (x - b), and (x - c). In this case, we have (x - 3), (x - [3 + i]), and (x - [3 - i]). The three factors are (x - 3)(x - 3 - i)(x - 3 + i).

Part 2: The two factors with complex terms are (x - 3 - i)(x - 3 + i), and multiplying these terms as a difference of two squares can give:
(x - 3)^2 - i^2 = x^2 - 6x + 9 - (-1) = x^2 - 6x + 10

Part 3: We now multiply (x^2 - 6x + 10) by the remaining factor of (x - 3). This results in the cubic expression:
(x^2 - 6x + 10)(x - 3)
= x^3 - 3x^2 - 6x^2 + 18x + 10x - 30
= x^3 - 9x^2 + 28x - 30
3 0
3 years ago
Help pls :) 10 points
Alexeev081 [22]

Answer:

sq root of 64 = 8, sq root of 81 = 9, 8 and 9

Step-by-step explanation:

Since Sq root of 64 = 8 and Sq root of 81 = 9 it is known that sq root of 66 is between  8 and 9

7 0
3 years ago
A farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. Find the maximum area he can close.
Margarita [4]

Answer:

Width of 37.5 feet and length of 50 feet will maximize the area.

Step-by-step explanation:

Let w represent width and l represent length of the pen.

We have been given that a farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. We are asked to find the dimensions that will maximize the area.

We can see from the attachment that the perimeter of the pens would be 4w+3l.

We can set our given information in an equation 4w+3l=300.

The area of the two pens would be A=2l\cdot w.

From perimeter equation, we will get:

w=\frac{300-3l}{4}

Substituting this value in area equation, we will get:

A=2l\cdot (\frac{300-3l}{4})

Since we need to maximize area, so we need to find derivative of area function as:

A=\frac{600l-6l^2}{4}

Bring out the constant:

A=\frac{1}{4}*\frac{d}{dl}(600l-6l^2)

A=\frac{1}{4}*(600-12l)

A=150-3l

Now, we will set our derivative equal to 0 as:

150-3l=0

150=3l

\frac{150}{3}=\frac{3l}{3}

50=l

Now, we will substitute l=50 in equation w=\frac{300-3l}{4} to solve for width as:

w=\frac{300-3(50)}{4}

w=\frac{300-150}{4}

w=\frac{150}{4}

w=37.5

Therefore, width of 37.5 feet and length of 50 feet will maximize the area.

8 0
3 years ago
What is 1/6 of 54= 1/3 of WHAT
hodyreva [135]

Answer:

27

Step-by-step explanation:

⅙ × 54 = ⅓ × x

9 = x/3

x = 27

7 0
3 years ago
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Select the correct locations on the graph. Select the lines that represent functions.
Paul [167]

Answer:

bruh there isnt a graph or anything we cant answer it

Step-by-step explanation:

7 0
3 years ago
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