Answer: Sorry no, I am going to answer this question
Step-by-step explanation: :) That is the answer to your question
Answer:
1/4
Step-by-step explanation:
Assuming the number cube is a six-faced die, you have
1 <u>2</u> 3 <u>4</u> 5 <u>6</u>
three odd numbers, and three even numbers. Therefore, the chance of it landing on an odd number or even number is 3/6, which equals 1/2. <em>That means you have a 50% chance to get an odd number, or an even number.</em>
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So, you have two die. Both have a 50/50 chance of getting an even or odd number. So what's the chance of one landing on an odd number, and the other landing on an even number?
- You would have a 25% chance for an <u>even</u> and then an <u>even</u> number
- You would have a 25% chance for an <u>odd</u> and then an <u>odd</u> number
- You would have a 25% chance for an <u>even</u> and then an <u>odd</u> number
- You would have a 25% chance for an <u>odd</u> and then an <u>even</u> number.
25% as a simplified fraction is 1/4. Therefore, 1/4 is your answer.
O=2a+2,
o/2-a/2=4 this is your system of equations,
It you wish to solve for apples, then simply substitute o from the first equation into the second equation...
(2a+2)/2-a/2=4 multiply both sides of the equation by 2
2a+2-a=8 combine like terms on the left side
a+2=8 subtract 2 from both sides
a=6
So Javier has 6 apples in the basket.
330-> -100 = 230, 230-> -100= 130
(I literally just watched a video how to do this, I never had to do it this way when I was in 2nd grade)
[130 final answer]
Hmm I think this is 1/2
Sorry if I'm wrong I'm not the best at math
