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yulyashka [42]
3 years ago
10

If f(x)=2x^2 +4 and g(x)=x-3,which number satisfies f(x)=(f•g) (x)

Mathematics
1 answer:
Nonamiya [84]3 years ago
8 0
(f\cdot g)(x)=f(x)\cdot g(x)\\\\
(f\cdot g)(x)=(2x^2+4)(x-3)\\
(f\cdot g)(x)=2x^3-6x^2+4x-12\\\\
2x^2+4=2x^3-6x^2+4x-12\\
2x^3-8x^2+4x-16=0\\
2x^2(x-4)+4(x-4)=0\\
(2x^2+4)(x-4)=0\\
2(x^2+2)(x-4)=0\\
\boxed{x=4}
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Answer:

Explanation:

AB = BC
=> Triangle ABC is an Isosceles Triangle
Thus, Angle C = Angle A
DE = BE
=> Triangle DEB is an Isosceles Triangle
Thus, Angle D = Angle B

Proof that triangle ABC and DEB are similar:

Angle DBE = Angle A (corresponding angle)
Angle BDE = Angle C (Both Triangle are Isosceles, if one pair of the angle are equal then the other pair should also be equal)

=> Triangle ABC ~ Triangle DEB (AA)

Therefore, Angle E = Angle B

Find angle B:

Angle C + Angle A + Angle B = 180
40 + 40 + angle B = 180
Angle B = 180 - 80
Angle B = 100 degree

But Angle B = Angle E = 100 degree

Therefore, Angle E = 100 degree
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Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

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3 years ago
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