How long does it take for females to get drunk off gin?

If a bond is currently trading at its face (par) value, then it must be the case that: A. the bond's yield to maturity is equ

strojnjashka [21]

Answer:

A) the bond's yield to maturity is equal to its coupon rate

Explanation:

If the bonds yield to maturity is equal to its coupon rate it means that the interest paid by the buyers on the face value of the bond is equal to the internal rate of return for the present value of future cash flow. Only in this scenario, a bond is traded at its face or par value.

7 0

3 years ago

A bag contains 9 red marbles, 5 white marbles, and 6 blue marbles. You draw 4 marbles out at random, without replacement. Find t

IRINA_888 [86]

a) 0.0260

b) 0.0681

Explanation:

a)

The bag contains:

r = 9 (number of red marbles)

w = 5 (number of white marbles)

b = 6 (number of blue marbles)

So, the total number of marbles in the bag at the beginning is:

$n=9+5+6=20$

At the 1st attempt, the probability of choosing a red marble is:

$p(r)=\frac{r}{n}=\frac{9}{20}$ (1)

At the 2nd attempt, the 1st red marble is not placed back, so now the number of marbles is (n-1), while the number of red marbles left is (r-1). So the probability of choosing another red marble at the 2nd attempt is

$p(r)=\frac{r-1}{n-1}=\frac{8}{19}$ (2)

With a similar argument, the probabilities of selecting a red marble in the 3rd and 4th attempt are

$p(r)=\frac{7}{18}$ (3)

$p(r)=\frac{6}{17}$ (4)

Therefore, the probability of drawing 4 red marbles in the first 4 attempts without replacing is:

$p(rrrr)=\frac{9}{20}\frac{8}{19}\frac{7}{18}\frac{6}{17}=\frac{3024}{116280}=0.0260$

b)

At the 1st draw, the probability that the marble is not red is:

$p(r^c)=1-p(r)=1-\frac{9}{20}=\frac{11}{20}$

At the 2nd draw, there are 9 red marbles left and 19 total marble left. So, the probability of NOT drawing a red marble is:

$p(r^c)=1-\frac{9}{19}=\frac{10}{19}$

At the 3rd draw, there are 9 red marbles left and 18 total marbles left. So, the probability of NOT drawing a red marble is:

$p(r^c)=1-\frac{9}{18}=\frac{9}{18}$

Finally, with a similar argument the probability of NOT drawing a red marble at the 4th and last attempt is:

$p(r^c)=\frac{8}{17}$

So, the total probability of drawing 4 non-red marbles in the first 4 attempts is:

$p(r^cr^cr^cr^c)=\frac{11}{20}\frac{10}{19}\frac{9}{18}\frac{8}{17}=\frac{7920}{116,280}=0.0681$

6 0

3 years ago

This graph shows the marginal cost of producing each

Margarita [4]

Answer:

D) Bike 4

Explanation:

Marginal cost is the additional expense associated with the production of an extra unit. Calculating marginal costs will involve isolating the expense of the last unit from the previous productions.

The graph has already isolated the cost of the extra unit from the previous output.

From the graph, Bike 4 has a marginal cost of 4.

6 0

2 years ago

Read 2 more answers

I hope I can see my channel grow supporting me would be awesome I want a career in this so please all help is wanted

timama [110]

Answer:

I hope you grow and become successful you deserve it and congratulations on that much subscribers

8 0

3 years ago

On March 15, a fire destroyed Blossom Company's entire retail inventory. The inventory on hand as of January 1 totaled $5300000.

Svet_ta [14]

Answer:

The value of inventory destroyed=$4,082,000

Explanation:

<em>The value of the inventory destroyed is the difference between the the cost of the total goods available for sale and the cost of goods sold</em>

The value of inventory destroyed = cost of goods available for sale - value of inventory sold

Cost of goods sold = 3540,000 - (20%× 3540,000)= 2,832,000

The cost of goods available for dale = opening inventory + purchases + freight charges

$5300000 + $1432000 + $182000 = 6,914,000

The value of inventory destroyed = 6,914,000 - 2,832,000 = 4082000

The value of inventory destroyed=$4,082,000

7 0

3 years ago