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3 years ago

Over a two hour time period a snail moved 64 inches. How far is this in yards?

Mathematics

2 answers:

ikadub [295]3 years ago

6 0

About 1.8 yards
There's 36 inches in a yard, so if you divide 64 by 1.8 you get the answer

lisabon 2012 [21]3 years ago

6 0

Well, there are 12 inches in a foot and three feet n an yard, so there are 36 inches in a yard so your answer would be 1 28/36 or simplified to 1 7/9.

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Factor completely 4u^2 + 28u + 49

nata0808 [166]

$4u^2+28u+49=4u^2+14u+14u+49=2u(u+7)+7(u+7)=\\ \\=(u+7)(2u+7)$

3 0

3 years ago

If triangle ocd ≅ triangle JAL, then which of the following statements are true?

Roman55 [17]

Answer:

I III and IV

Step-by-step explanation:

8 0

2 years ago

To complete this component you will need to insert parentheses in Expression 2 to change the order of operations so the expressi

Alika [10]

Given:

The expression is $5+4\times 2+6-2\times 2-1$ .

To find:

The position of parentheses inserted in the expression to get the value 19

Step-by-step explanation:

We have,

$5+4\times 2+6-2\times 2-1$

Now,

$(5+4)\times 2+6-2\times 2-1=9\times 2+6-4-1$

$(5+4)\times 2+6-2\times 2-1=18+6-5$

$(5+4)\times 2+6-2\times 2-1=18+1$

$(5+4)\times 2+6-2\times 2-1=19$

There are more ways to apply the parenthesis, but we do not get 19.

$5+4*\left(2+6\right)-2*2-1=32\neq 19$

$5+4*2+\left(6-2\right)*2-1=20\neq 19$

$5+4*2+6-2*\left(2-1\right)=17\neq 19$

And many more possibilities.

Therefore, the expression after inserting the parentheses is $(5+4)\times 2+6-2\times 2-1$ .

6 0

3 years ago

Who can help me to solve these questions please?

ankoles [38]

Using the given information, length of QR = 16.6 cm

The area of the trapezium is 304.5 cm²

<h3>Calculating area of a trapezium</h3>

From the question we are to calculate the length of QR and the area of trapezium PQRS

In the given diagram,

Let the midpoint of PS be T

Then, we can write that

|OP|² = |OT|² + |PT|² (<em>Pythagorean theorem</em>)

|OP| = radius = 13 cm

|PT| = 1/2 × PS = 1/2 × 24 cm = 12 cm

∴ 13² = |OT|² + 12²

169 = |OT|² + 144

|OT|² = 169 -144

|OT|² = 25

|OT| = √25

|OT| = 5 cm

Also, let the midpoint of QR be U

Then, we can write that

|OQ|² = |OU|² + |QU|² (<em>Pythagorean theorem</em>)

|OQ| = radius = 13 cm

From the given information,

The distance of QR from O is twice the distance of PS from O

∴ |OU| = 2 × |OT|= 2 × 5 cm = 10cm

Thus,

13² = ||² + 12²

169 = 10² + |QU|²

|QU|² = 169 -100

|QU|² = 69

|QU| = √69

|QU| = 8.3 cm

Now,

Length of QR = 2 × |QU| = 2 × 8.3 cm

Length of QR = 16.6 cm

Area of the trapezium = 1/2(|QR| + |PS|) × |TU|

Area of the trapezium = 1/2(16.6 + 24) × 15

NOTE: |TU| = |OT| + |OU|

Area of the trapezium = 1/2(40.6) × 15

Area of the trapezium = 20.3 × 15

Area of the trapezium = 304.5 cm²

Hence, the area of the trapezium is 304.5 cm²

Learn more on Calculating area of trapezium here: brainly.com/question/3435635

#SPJ1

7 0

2 years ago

A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What

vladimir2022 [97]

Answer:

The perimeter of the triangle is $12\ units$

Step-by-step explanation:

Let

$A(-3,1),B(1,1),C(1,-2)$

we know that

The perimeter of triangle is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-3,1),B(1,1)$

substitute in the formula

$AB=\sqrt{(1-1)^{2}+(1+3)^{2}}$

$AB=\sqrt{(0)^{2}+(4)^{2}}$

$AB=4\ units$

step 2

Find the distance BC

$B(1,1),C(1,-2)$

substitute in the formula

$BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}$

$BC=\sqrt{(-3)^{2}+(0)^{2}}$

$BC=3\ units$

step 3

Find the distance AC

$A(-3,1),C(1,-2)$

substitute in the formula

$AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}$

$AC=\sqrt{(-3)^{2}+(4)^{2}}$

$AC=5\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=4+3+5=12\ units$

6 0

3 years ago