Hmm
what you do is try to eliminate 1 variable in 2 equaions first
we can elminate x's in first and 2nd equation
add first and 2nd equation
x+3y-2z=10
<u>-x-2y+z=-7 +</u>
0x+y-z=3
y-z=3
multiply 2nd equation by 3 and add to last one
-3x-6y+3z=-21
<u>3x+9y-5z=28 +</u>
0x+3y-2z=7
3y-2z=7
we now have
y-z=3
3y-2z=7
multiply first equation by -2 and add to 2nd
-2y+2z=-6
<u>3y-2z=7 +</u>
y+0z=1
y=1
now we can sub back
y-z=3
1-z=3
minus 1
-z=2
times -1
z=-2
sub baack into any equation
x+3(1)-2(-2)=10
x+3+4=10
x+7=10
minus 7
x=3
x=3
y=1
z=-2
(3,1,-2)
Let the required number be x, then
x + 3,080 = 5,082
x = 5,082 - 3,080
x = 2,002
Answer:
14/4 or 7/2
Step-by-step explanation:
6 - (-7)
---------
-3 - (-7)
When you subtract a - its really just adding
Answer:
46
Step-by-step explanation:
With those problems if you are not given a picture is good we draw one.
Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW then
m < XVY = m < YVW
2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms
2x-x = 15-7, combine like terms
x = 8
From the picture and the given we see that
m < XVW = m < XVY + m < YVW
m < XVW = 2x+7 + x+15 , combine like terms
m < XVW = 3x + 22, substitute x for 8
m < XVW = 3*8 + 22
m < XVW = 46
Check our work:
m < XVY = 2x+7 = 2*8 +7 = 16 +7 = 23
m < YVW = x+15 = 8 +15 = 23
m < XVW = m < XVY + m < YVW = 23+23 =46