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3 years ago

Solve for x: 12=-2(x+8)

Mathematics

2 answers:

liberstina [14]3 years ago

7 0

Your answer would be : x=-14

erastova [34]3 years ago

6 0

12=-2(x+8)
-----------
Simplify and flip
12=-2(x+8)
12=(-2)(x)+(-2)(8)
12=-2x+-16
12=-2x-16
-2x-16=12
-------------
Add 16 on each side
-2x-16+16=12+16
-2x=28
-----------------
Now, divide each side by -2
-2x ÷ -2 = 28 ÷ -2
x = -14

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If 2 is added to both the numerator and denominator of a fraction its value becomes half. If two is subtracted from both the num

Hitman42 [59]

Answer:

The original fraction is $\frac{6}{14}$ .

Step-by-step explanation:

Solution,

Let the fraction be' $\frac{x}{y}$ '.

Where 'x' is the numerator and 'y' is the denominator.

Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.

So, framing the above sentence in equation form, we get;

$\frac{x+2}{y+2}=\frac{1}{2}$

On using cross multiplication method, we get;

$2(x+2)=y+2\\\\2x+4=y+2\\\\2x+4-2=y\\\\\therefore\ y=2x+2\ \ \ \ equation\ 1$

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.

So, framing the above sentence in equation form, we get;

$\frac{x-2}{y-2}=\frac{1}{3}$

On using cross multiplication method, we get;

$3(x-2)=y-2\\\\3x-6=y-2\\\\3x-y=-2+6\\\\3x-y=4 \ \ \ \ equation\ 2$

Now Substituting the equation 1 in equation 1 we get;

$3x-y=4\\\\3x-(2x+2)=4\\\\3x-2x-2=4\\\\3x-2x=4+2\\\\x=6$

Now Substituting the value of x in equation 1 we get;

$y=2x+2\\\\y=2\times6+2 = 14$

Hence The original fraction is $\frac{6}{14}$ .

4 0

3 years ago

Can you help me please

Olenka [21]

Answer:

$log_372 = 3.8928$

Step-by-step explanation:

Given

$log_38 = 1.8928$

Required

Evaluate $log_372$

We have:

$log_372 = log_3(8 *9)$

Apply law of logarithm

$log_372 = log_38 +log_39$

Express 9 as 3^2

$log_372 = log_38 +log_33^2$

Evaluate the exponents

$log_372 = log_38 +2log_33$

$log_33 = 1$ .

So:

$log_372 = log_38 + 2 * 1$

$log_372 = log_38 + 2$

Substitute $log_38 = 1.8928$

$log_372 = 1.8928 + 2$

$log_372 = 3.8928$

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Aleksandr [31]

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kirza4 [7]

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3 0

3 years ago

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