How to solve the x and y intercepts

Mathematics

2 answers:

romanna [79]3 years ago

8 0

Hello!

To solve for the x-intercepts, you need to use the zero product property in order to solve for your x's.

3x - 10 = 0 x - 1 = 0
+ 10 + 10 + 1 + 1
3x = 10 x = 1
/3 /3
x = 10/3

To solve for the y-intercept, you need to substitute x for 0.

f(0) = 3x² - 13x + 10
f(0) = 3(0)² - 13(0) + 10
f(0) = 10

Therefore, your x-intercepts are x = 10/3 and 1 and your y-intercept is 10.

Sever21 [200]3 years ago

4 0

To find the x-intercept of a given linear equation, plug in 0 for 'y' and solve for 'x'. To find the y-intercept, plug 0 in for 'x' and solve for 'y'. In this tutorial, you'll see how to find the x-intercept and the y-intercept for a given linear equation.

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8 0

4 years ago

Does anyone know the answer to this?

denis23 [38]

Answer:

$g(x) = 3(x - 12)^{2} - 5$

Step-by-step explanation:

Horizontal translations = f(x ± h)

Reflection over the x-axis = - f(x)

For the function $f(x) = - 3(x - 4)^{2} +5$ , translating the parabola 8 units to the right means the horizontal shift of the graph, adding (- 8) to the h input. This is represented by: $g(x) = - 3(x - 12)^{2} +5$ .

Next, flipping the graph over the x-axis represent a reflection. Since we currently have a negative coefficient for the value of a, then the opposite of a negative coefficient is a positive coefficient.

Therefore, the rightward horizontal translation of 8 units, and the reflection of the graph over the x-axis is represented by:

$g(x) = 3(x - 12)^{2} - 5$

For your reference, the three images below shows the transformations on the graph. The first image is the original function (in red parabola). The second image represents the reflection over the x-axis (green parabola). The third image shows the horizontal shift, 8 units to the right (blue parabola). If you take note of the varying values in vertices, (h, k ) for the three graphs, you'll see that the original vertex was (4, 5) and the new vertices for the transformations are (4, -5) for the reflection and (12, -5) for the shift.