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docker41 [41]
2 years ago
7

Use the information below to complete the problem: p(x) = (1)/(x + 1)

Mathematics
1 answer:
bija089 [108]2 years ago
8 0

Given:

The functions are:

p(x)=\dfrac{1}{x+1}

q(x)=\dfrac{1}{x-1}

To find:

The rational expression for p(x)-q(x).

Solution:

We have,

p(x)=\dfrac{1}{x+1}

q(x)=\dfrac{1}{x-1}

Now,

p(x)-q(x)=\dfrac{1}{x+1}-\dfrac{1}{x-1}

p(x)-q(x)=\dfrac{(x-1)-(x+1)}{(x+1)(x-1)}

p(x)-q(x)=\dfrac{x-1-x-1}{x^2-1^2}             [\because a^2-b^2=(a-b)(a+b)]

p(x)-q(x)=\dfrac{-2}{x^2-1}

Therefore, the required rational expression for p(x)-q(x) is \dfrac{-2}{x^2-1}.

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Check the picture below.

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A garden supply store sells two types of lawn mowers. The smaller mower costs $249.99 and the larger mower costs $329.99. If the
Butoxors [25]
Therefore, ' 19 ' smaller lawn mover and '11' larger lawn mover were sold.
Step-by-step explanation:
Given:
let the smaller lawn mover be 'x'
let the larger lawn mower be 'y'
According to condition total mover will be
................( 1 )
and total cost will be given as
................( 2 )
To Find:
x =? and y =?
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3 0
2 years ago
Solve the literal equation for x. <br><br> k= nx - 3x
Amiraneli [1.4K]

answer:X=k/n-3

explain:move all terms to the left side and set equal to zero. then set each factor equ to zero!

I hope this helps

7 0
2 years ago
Read 2 more answers
In the accompanying diagram of right triangle ABC, the hypotenuse if AB, AC = 3, BC = 4, and AB = 5. Sin B is equal to
Trava [24]

Answer:sin(B)=\frac{3}{5}

Step-by-step explanation:

We are given that a triangle ABC is a Right Angled Triangle. The side AB is hypotenuse, so the angle opposite to side AB which will be angle C is a Right Angle (measures 90 degrees)

We have the side length of all 3 sides. Based on this information, we can construct a triangle with given measures. The triangle is shown in the attached image.

We have to find the value of Sin(B). Sin of an angle is defined as:

sin(\theta)=\frac{\text{Opposite Side}}{\text{Hypotenuse}}

The side opposite to angle B is AC with a length of 3 and hypotenuse is side AB with length 5. So Sin of angle B would be:

sin(B)=\frac{3}{5}

8 0
3 years ago
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
2 years ago
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