<h3>
Answer: 11/20</h3>
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Work Shown:
x = unknown horizontal length
1/5 = 0.2
Perimeter = 2*(width + length)
P = 2*(0.2 + x)
P = 0.4 + 2x
Set this equal to the given perimeter of 1 & 1/2 = 1.5 and solve for x
0.4 + 2x = 1.5
2x = 1.5-0.4
2x = 1.1
x = (1.1)/2
x = 0.55
x = 55/100
x = (5*11)/(5*20)
x = 11/20
Split the triangle into a 30-60-90 triangle. Since you have LM from that triangle, you can figure out the other sides. Then, using the leg from that triangle, the one next to it is a 45-45-90 triangle, meaning it's isosceles.
KM = 30 + 10√3
KL = 10√6
(sorry i'm not too sure if my "reasons" for statement/reason is correct)
Answer:
5ln3=ln(3^5)
Step-by-step explanation:
Given: 5ln(3)
Use rule: alog(b)=log(b^a), aln(b)=ln(b^a) (doesn't matter what the log base is)
Apply rule: ln(3^5)
For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has
• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5
• height = <em>x</em> ² + 2
• thickness = d<em>x</em>
and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.
Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:

Simplify :
12+-5x+6x=4
combine like terms :
-5x+6x=1x
12+1x=4
solving :
12+1x=4
solving for variable ‘x’
move all terms containing x to the left, all other terms to the right, add ‘-12’ to each side of the equation
12+-12+1x=4+-12
combine like terms:
then divide each side
your answer : x=-8