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Ierofanga [76]
2 years ago
12

In a term,it’s factor which is a number in front of a variable

Mathematics
1 answer:
qaws [65]2 years ago
8 0

Answer: Coefficient

For example, the term 7x has the coefficient 7 in front of the variable x.

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The drama club is selling tickets for a play. The profit, y, is
Goshia [24]

Answer:

80 tickets

Step-by-step explanation:

Given the profit, y, modeled by the equation, y = x^2 – 40x – 3,200, where x is the number of tickets sold, we are to find the total number of  tickets, x, that need to be sold for the drama club to break  even. To do that we will simply substitute y = 0 into the given the equation and calculate the value of x;

y = x^2 – 40x – 3,200,

0 = x^2 – 40x – 3,200,

x^2 – 40x – 3,200 = 0

x^2 – 80x  + 40x – 3,200 = 0

x(x-80)+40(x-80) = 0

(x+40)(x-80) = 0

x = -40 and x = 80

x cannot be negative

Hence the total number of  tickets, x, that need to be sold for the drama club to break  even is 80 tickets

8 0
2 years ago
Help on test pls! asap!!
Tanzania [10]

Answer:

1) D it doesn't pass the line test

2)B

3)A C F

4 0
2 years ago
Which of the following is not a right triangle?
sergeinik [125]
8 15 17 i think no clue really
8 0
2 years ago
Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g
olchik [2.2K]

If x is the first number in the progression, and r is the common ratio between consecutive terms, then the first four terms in the progression are

\{x,xr,xr^2,xr^3\}

We want to have

\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}

In the second equation, we have

xr^3-xr=xr(r^2-1)=36

and in the first, we have

xr^2-x=x(r^2-1)=12

Substituting this into the second equation, we find

xr(r^2-1)=12r=36\implies r=3

So now we have

\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32

Then the four numbers are

\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}

4 0
3 years ago
3. Consider the sequence,-8, -5, -2, 1, ...
Naddik [55]

Answer:

a) a_n=3\,n-11

b) a_{20}=49

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

a_n=a_1+(n-1)\,d

That in our case would give:

a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11

b)

Therefore, the term number 20 can be calculated from it:

a_{20}=3\,(20)-11=60-11=49

c) in order to find which term renders 20, we use the general form we found in step a):

a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17

so term number 17 is the one that renders a value of 40

5 0
2 years ago
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