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Mice21 [21]
4 years ago
10

Nick made orange juice by mixing orange juice concentrate with water. Nick's friend said that the orange juice tasted very dilut

ed. What does his friend's statement mean? There is an equal amount of juice concentrate compared to water. There is a large amount of juice concentrate compared to water. There is a very small amount of juice concentrate compared to water.
Chemistry
2 answers:
mojhsa [17]4 years ago
6 0

Answer:

There is a very small amount of juice concentrate compared to water.

Explanation:

Alenkasestr [34]4 years ago
3 0

If the orange juice tasted very diluted that means that there was too much water and not enough orange juice. This being said the answer would be There is a very small amount of juice concentrate compared to water.

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An aluminum block has a mass of 82.0 g and a volume of 12.8 cm3. what is the block's density to the nearest g/cm3?
aksik [14]
Density is mass over volume. If you put it into a formula it would look like this:

D = \frac{m}{v}

Based on the problem given, you can see that the mass of the aluminum block is 82.0 g and the volume is 12.8 cm3. Just put that into your equation and solve for it:

D = \frac{m}{V}=  \frac{82.0g}{12.8cm^{3} }  = 6.4g/ cm^{3}

The answer is then letter C.


6 0
4 years ago
a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. what is its density? a. 638 g/cm3 b.
Juliette [100K]
Volume = 3 cm × 3cm × 3cm
             =  27 cm ³

Mass  =  213 g

Density  =  \frac{MASS}{VOLUME}
 
              = <span>\frac{213 g}{27 cm ^{3} }
</span> 
<span>              =  7.89 g / cm³

Thus answer is D.</span>
8 0
3 years ago
Read 2 more answers
N2 + 3H2, -&gt; 2NH3<br> If I have 50.6 L of N2 and excess H2, how many liters of NH3 can I produce?
Anastaziya [24]

Answer:

C. 101.2 L

Explanation:

N2 + H2= NH3

Balancing it,

N2 + 3 H2 = 2.NH3

(1 mol) (3 mol) (2 mol)

which means

1 molecule of nitrogen reacts with 3 molecule of hydrogen to form ammonia.

Likewise,

50.6 l of nitrogen reacts with 50.6 × 3= 151.8 l of hydrogrn to form 50.6 × 2= 101.2 l of ammonia.

3 0
3 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
Are carbon atoms a pure substance or a mixture?
vichka [17]

Answer:

Substance

Explanation:

7 0
3 years ago
Read 2 more answers
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