<u>Answer:</u>
<u>For 1:</u> The product is phosphoric acid and the solution is acidic in nature.
<u>For 2:</u> The product is sodium hydroxide and the solution is basic in nature.
<u>For 3:</u> The product is nitric acid and the solution is acidic in nature.
<u>Explanation:</u>
For the given options:
(1): When diphosphorus pentoxide reacts with water, it leads to the formation of phosphoric acid, which makes the solution acidic in nature.
The chemical equation for the reaction follows:

(2): When disodium oxide reacts with water, it leads to the formation of sodium hydroxide, which makes the solution basic in nature.
The chemical equation for the reaction follows:

(3): When dinitrogen pentoxide reacts with water, it leads to the formation of nitric acid, which makes the solution acidic in nature.
The chemical equation for the reaction follows:

Answer:
1.1713 moles
Explanation:
RFM of N2O5=108
Moles of N2O5= mass/RFM= 63.25/108=0.5856 moles
Mole ratio of N2O5:NO2= 2:4
Therefore moles of NO2= 4/2*0.5856= 1.1713 moles
Answer:
2CH3CHOHCH3 + 9O2 ----> 6CO2 + 8H2O
Explanation:
It will be a clean burn ( no smoke).
<span>The answer to this question would be: a double replacement reaction
In double replacement reaction or metathesis, the reaction will result in two new compound. The cation from the molecule reaction is switching with the cation from other molecules.
In contrast to the double replacement reaction, in single replacement reaction the molecule made in just one. In this case, the compound is just swapping its molecule with a more reactive one, results in a more stable compound.</span>
Answer:
32
Step-by-step explanation:
There are two ways you can count the valence electrons.
A. From the Periodic Table
1 × P (Group 15) = 5
4 × O (Group 16) = 4 × 6 = 24
+3 e⁻ (for the charges) = <u> 3</u>
Total = 32
B. From the Lewis structure
In the <em>Lewis structure</em> (below), each line (bond) represents a pair of bonding electrons, and each dot represents an unbound electron (half a lone pair).
5 lines (bonds) = 5 × 2 = 10
3 single-bonded O atoms = 3 × 6 = 18
1 double-bonded O atom = <u> 4</u>
Total = 32