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enyata [817]
3 years ago
6

N2 + 3H2, -> 2NH3 If I have 50.6 L of N2 and excess H2, how many liters of NH3 can I produce?

Chemistry
1 answer:
Anastaziya [24]3 years ago
3 0

Answer:

C. 101.2 L

Explanation:

N2 + H2= NH3

Balancing it,

N2 + 3 H2 = 2.NH3

(1 mol) (3 mol) (2 mol)

which means

1 molecule of nitrogen reacts with 3 molecule of hydrogen to form ammonia.

Likewise,

50.6 l of nitrogen reacts with 50.6 × 3= 151.8 l of hydrogrn to form 50.6 × 2= 101.2 l of ammonia.

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Answer:

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3 years ago
An inflatable toy starts with 1.05 moles of air and a volume of 5.17 liters. When fully inflated, the volume is 8.00 liters. If
padilas [110]

Answer:-  1.62 moles

Solution:- At constant temperature and pressure, volume is directly proportional to the moles of the gas.

\frac{V_1}{V_2}=\frac{n_1}{n_2}

from given data, V_1 = 5.17 L, n_1 = 1.05 moles

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Let's plug in the values in the formula:

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On cross multiply:

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5 0
3 years ago
What is the mass of KNO3 should be used to prepare 2.00 L of a 0.700 M solution?
Dmitry [639]

Answer:

141.4g

Explanation:

Moles= conc. ×vol

m/M = 0.7×2

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m= 141.4g

3 0
3 years ago
A student measures the mass of a sample as 9.64 g. Calculate the percentage error, given that the correct mass is 9.80 g.
rosijanka [135]

Answer:

<h3>The answer is 1.63 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual mass = 9.80 g

error = 9.80 - 9.64 = 0.16

We have

p(\%) =  \frac{0.16}{9.80}  \times 100 \\  = 1.632653061...

We have the final answer as

<h3>1.63 %</h3>

Hope this helps you

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4 years ago
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svetlana [45]

Answer:

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3 years ago
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