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2 years ago

N2 + 3H2, -> 2NH3 If I have 50.6 L of N2 and excess H2, how many liters of NH3 can I produce?

Chemistry

1 answer:

Anastaziya [24]2 years ago

3 0

Answer:

C. 101.2 L

Explanation:

N2 + H2= NH3

Balancing it,

N2 + 3 H2 = 2.NH3

(1 mol) (3 mol) (2 mol)

which means

1 molecule of nitrogen reacts with 3 molecule of hydrogen to form ammonia.

Likewise,

50.6 l of nitrogen reacts with 50.6 × 3= 151.8 l of hydrogrn to form 50.6 × 2= 101.2 l of ammonia.

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<h3>What is the heat of solution?</h3>

We know that in a calorimeter, there is no loss or gain of energy. It is a good example of a closed system.

Number of moles of KOH = 11.9-g/56 g/mol = 0.21 moles

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Then;

ΔH = mcθ

ΔH = 100g * 4.184 j/g⋅°c * 26.0 ∘c = 10.88 kJ

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2 years ago

How many moles of phosphoric acid would be needed to produce 15 grams of water?

bekas [8.4K]

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<h3>Further explanation</h3>

Given

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Required

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