Answer:
Molarity= 0.071M
Explanation:
Molar mass of NaNO3= 23+14+(16*3)=85
n= m/M = 30/85= 0.353mol
V= 5L
Applying
n= CV
0.353= C×5
Simplify
C= 0.071M
Answer:
72.71 %
Explanation:
For oxygen: mass % O = (mass of 1 mol of oxygen/mass of 1 mol of CO2) x 100. mass % O = (32.00 g / 44.01 g) x 100. mass % O = 72.71 %
HOPED THIS HELPED YOU OUT
A brainliest is always appreciated.
Answer:
due to the bicarbonate of CaCO3
Its just called a test tube holder
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