What is the least common multiple of 8 and 12

What is the distance?

Arlecino [84]

Answer:

.25 it 1/4 or an inch should be correct

5 0

3 years ago

Help and explain how you got it. no trolling or report!

Galina-37 [17]

Answer:

I am 100% confident in my calculations. I'm not 100% sure about interpreting. Sorry I can't be of more help.

Part A:

Median: 4.5

IQR: 3.5

Mode: 6

I think the median/IQR is a better measure of center and variability because the range of data is so big (10 - 0 = 10), and the data skews to the right with the 6s.

Part B:

I would say no. It is the one that occurs most frequently, but there are many more times she rides less than 6, which is why the median is 4.5

Step-by-step explanation:

Mean: 4.714

MAD: 2.43

Median: 4.5

IQR: 3.5

Mode: 6

the number set in order:

0, 2, 2, 2.5, 2.5, 3, 4, 5, 6, 6, 6, 8, 9, 10

The median (middle number) is two numbers: 4 and 5, so the median is 4.5

The first quartile/Q1 (middle of the bottom half of data) is 2.5, the third quartile/Q3 (middle of the top half of data) is 6. So the IQR (interquartile range) is 6 - 2.5 = 3.5

The mean is the sum of the numbers divided by the quantity of the numbers, so 66/14 = 4.714

the mean absolute deviation is found by calculating the mean, and then finding the absolute value of the difference between each number of the set and the mean...then adding those together and finding the mean of that set. Labor intensive, but that's 34/14 = 2.42857143

4 0

3 years ago

Rachel made $176 for 11 hours of work.

elena55 [62]

Answer:

8 hours

Step-by-step explanation:

11 hours = $176

⇒ 1 hour = $176 ÷ 11 = $16

To determine how many hours she would have to work to make $128, divide $128 by $16:

⇒ number of hours = $128 ÷ $16

= 8 hours

6 0

2 years ago

Read 2 more answers

A rectangle measures 2 1/2 inches by 1 5/16 inches. What is its area?

Norma-Jean [14]

Answer:

it would be 3.28125

Step-by-step explanation:

do base times height to get the area

6 0

3 years ago

he one‑sample t statistic from a sample of n = 23 observations for the two‑sided test of H 0 : μ = 15 versus H α : μ > 15 has

DedPeter [7]

Answer:

$t = 2.24$

The first step is calculate the degrees of freedom, on this case:

$df=n-1=23-1=22$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(22)}>2.24)=0.01776$

And for this case we can conclude that:

$0.01 < p_v < 0.025$

And we will reject the null hypothesis at $\alpha=0.025$ since $p_v < \alpha$

Step-by-step explanation:

Data given and notation

$\bar X$ represent the mean height for the sample

$s$ represent the sample standard deviation

$n=23$ sample size

$\mu_o =15$ represent the value that we want to test

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

For this case the statistic is given:

$t = 2.24$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=23-1=22$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(22)}>2.24)=0.01776$

And for this case we can conclude that:

$0.01 < p_v < 0.025$

And we will reject the null hypothesis at $\alpha=0.025$ since $p_v < \alpha$

5 0

3 years ago