Answer:
26
Step-by-step explanation:
5x+6y
substitute x=16 and y=-9:
5*16+6*(-9)
=80-54
=26
Answer:
1.66
Step-by-step explanation:
Calculation to find the standard deviation for the random variable X of the number of students who work full time in samples of size
Using this formula
Standard deviation(X)=√np(1−p)
Where,
n represent the number of students=16
p represent the percentage of all students who work full time=22
Let plug in the formula
Standard deviation(X)=√16(0.22)(1−0.22)
Standard deviation(X)=√(3.52)(0.78)
Standard deviation(X)=√2.7456
Standard deviation(X)=1.656
Standard deviation(X)=1.66 (Approximately)
Therefore the standard deviation for the number of students who work full time in samples of size 16 will be 1.66
Answer:
Hello some parts of your question is missing below is the missing part
answer : A) p-value = 0.0019 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Step-by-step explanation:
A) using a 0.05 level of significance and test for independence of the quality of management
Test statistic :
∑ ( Oi - Ei )^2 / Ei
= [(40-35)^2 / 35 ] + [(25-24.5)^2 / 24.5 ] + [(5-10.5)^2 / 10.5] + [(35-40)^2 / 40] + [(35-28)^2 / 28] + [(10-12)^2 / 12] + [ (25-25)^2 / 25 ] + [(10-17.5)^2 / 17.5 ] + [(15-7.5)^2 / 7.5] = 17.03
p-value = 0.0019
Df = 4 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Mmm... I think it is 5/8... I think.