61 would be the most simplified without expressions
Answer:
- 60 pounds of $6.13 nuts and
- 40 pounds of $7.13 nuts
Step-by-step explanation:
- $6.13 nut = x pounds
- $7.13 nut = y pounds
<u>Equations:</u>
- 6.13x + 7.13y = 6.53*100
- x + y = 100
<u>Solve by substitution x = 100 - y:</u>
- 6.13(100 - y) + 7.13y = 653
- 613 - 6.13y + 7.13y = 653
- y = 653 - 613
- y = 40
<u>Find x:</u>
Answer:
2.85 UK£
Step-by-step explanation:
To calculate the final price after the percent off, subtract the savings amount from the initial price. For example, calculate the final price of a $40 item with 15% off – remember this is a $6 savings.
Answer:
x-12=66 or 78 -12 =68
Step-by-step explanation:
3+2= 5 ||| 5 is the answer, sum
difference 12 || difference= subtract
is = equals
What I think ~
This question is incomplete, the complete question is;
An aircraft seam requires 27 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.)
If 25% of all seams need reworking, what is the probability that a rivet is defective?
Answer:
the probability that a rivet is defective is 0.0106
Step-by-step explanation:
Given the data in the question,
let event X represent seam fails and event B represent rivet fails.
now, 25% of all seams need reworking;
i.e P(X) = 25% = 0.25
the probability that a rivet is defective will be;
P( A ) = 1 - P( B' )²⁷
so
0.25 = 1 - P( B' )²⁷
P( B' )²⁷ = 1 - 0.25
P( B' )²⁷ = 0.75
P( B' ) =
P( B' ) = 0.9894
so
P( B ) = 1 - 0.9894
P( B ) = 0.0106
Therefore, the probability that a rivet is defective is 0.0106