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IceJOKER [234]
4 years ago
13

WILL GIVE BRAINLIEST

Mathematics
2 answers:
Serggg [28]4 years ago
5 0
Since IK is the sum of Lines JK and IJ, we set IK = JK + IJ.
9x-19 = 5x+12 + x-4
Combining like terms,
9x-19 = 6x+8
adding 19 and subtracting 6x,
3x = 27
dividing by 3,
x = 9
Plugging in x for JK, IK, and IJ:
JK = 5*9 + 12
= 45 + 12
=57

IK = 9*9-19
=81-19
=62

IJ = 9-4
= 5

Since IJ is 5, JK is 57, and IK is 62, the answer is B.
Cloud [144]4 years ago
4 0
The whole line is IK.
This means that IJ + JK = IK

IJ = x - 4
IK = 9x - 19
JK = 5x + 12

(x - 4) + (5x + 12) = 9x - 19
6x + 8 = 9x - 19
8 = 3x - 19
27 = 3x
9 = x

Now that you have x, insert it into each of the segments.
IJ = x - 4
IJ = 9 - 4
IJ = 5

IK = 9x - 19
IK = 9(9) - 19
IK = 81 - 19
IK = 62

JK = 5x + 12
JK = 5(9) + 12
JK = 45 + 12
JK = 57

So the answer would be:
B. IJ = 5, JK = 57, IK = 62
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