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IceJOKER [234]
3 years ago
13

WILL GIVE BRAINLIEST

Mathematics
2 answers:
Serggg [28]3 years ago
5 0
Since IK is the sum of Lines JK and IJ, we set IK = JK + IJ.
9x-19 = 5x+12 + x-4
Combining like terms,
9x-19 = 6x+8
adding 19 and subtracting 6x,
3x = 27
dividing by 3,
x = 9
Plugging in x for JK, IK, and IJ:
JK = 5*9 + 12
= 45 + 12
=57

IK = 9*9-19
=81-19
=62

IJ = 9-4
= 5

Since IJ is 5, JK is 57, and IK is 62, the answer is B.
Cloud [144]3 years ago
4 0
The whole line is IK.
This means that IJ + JK = IK

IJ = x - 4
IK = 9x - 19
JK = 5x + 12

(x - 4) + (5x + 12) = 9x - 19
6x + 8 = 9x - 19
8 = 3x - 19
27 = 3x
9 = x

Now that you have x, insert it into each of the segments.
IJ = x - 4
IJ = 9 - 4
IJ = 5

IK = 9x - 19
IK = 9(9) - 19
IK = 81 - 19
IK = 62

JK = 5x + 12
JK = 5(9) + 12
JK = 45 + 12
JK = 57

So the answer would be:
B. IJ = 5, JK = 57, IK = 62
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Can someone my answers
erik [133]

Answer:

Option 2 is correct that is \frac{x+2}{x+9}  and x\neq-9and x\neq-12

Step-by-step explanation:

We have been given with the expression \frac{x^2-10x-24}{x^2-3x-108}

We will simplify  the given expression by factorisation we will get \frac{x^2-12x+2x-24}{x^2-12x+9x-108}  

Taking x as common from first two terms in numerator and 2 from last two terms in numerator

Similarly, take x common from first two terms and 9 from last two terms in denominator we will get

\frac{x(x-12)+2(x-12)}{x(x-12)+9(x-12)}

After arranging the terms we will get \frac{(x+2)(x-12)}{(x+9)(x-12)}

Taking out the common factor which is (x-12)  from numerator and denominator it will get cancelled we will get

\frac{(x+2)}{(x+9)}

Hence, Option 2 is correct that is \frac{x+2}{x+9}  and x\neq-9and x\neq-12

6 0
3 years ago
Find the value of x. Round to the<br> nearest tenth.<br> X<br> 12<br> x = [?]
DiKsa [7]

Answer:

63.4

Step-by-step explanation:

Tan = opposite/adjacent

Tan x = tan-1

Tan-1 (6/12)

=63.43494882

63.4

8 0
3 years ago
How do I solve x(3x-17)=0 using the square root property
scZoUnD [109]

Answer:

x = 0 or x = \frac{17}{3}

Step-by-step explanation:

We have the quadratic equation of variable x and we have to solve the equation using the square root property.

Now, we have x(3x - 17) = 0

⇒ 3x² - 17x = 0

⇒ 3(x^{2}  - \frac{17}{3}x ) = 0

⇒ x^{2} - 2 \times (\frac{17}{6}) \times x + (\frac{17}{6} )^{2} = (\frac{17}{6} )^{2}

⇒ (x - \frac{17}{6})^{2} = (\frac{17}{6} )^{2}

Now,square rooting both sides we get,  

x - \frac{17}{6} = \pm\frac{17}{6}

Therefore, either x = 0 or x = \frac{17}{3} (Answer)

8 0
3 years ago
Can anyone plz help me? with this math question?
asambeis [7]

Answer:

it May be SAS postulate

4 0
3 years ago
Given the following system of equations: −x + y = 2 2x + 4y = 32 What action was completed to create this new equivalent system
tiny-mole [99]

Answer:

you just need to devide by 2 the second equation

Step-by-step explanation:

  • -x + y = 2 (you leave it as it is)

  • 2x + 4y =32 => 2x/2 +4y/2 = 32/2

=> x + 2y =16

we can devide or multiply in an equation by any number we want, as long as we do it to every term.

6 0
3 years ago
Read 2 more answers
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