The graph of the function f(x) = ax2 + bx +c (where a, b, and c are real and nonzero) has two x-intercepts. Explain how to find

Question

mezya [45]

3 years ago

12

The graph of the function f(x) = ax2 + bx +c (where a, b, and c are real and nonzero) has two x-intercepts. Explain how to find

the other x-intercept if one x-intercept is at (-b/a2 +3,0)

Mathematics

2 answers:

sveticcg [70] · Answer 1 · 2022-01-20T18:14:43+03:00

Recorded response:

The axis of symmetry is -b/2a

The x-intercept shown is 3 units away from the axis of symmetry.

The other x-intercept also must be 3 units away from the axis of symmetry but on the opposite side.

Subtract 3 from the axis of symmetry.

The other x-intercept is (-b/2a-3,0)

Olin [163] · Answer 2 · 2022-01-20T16:41:04+03:00

Olin [163]3 years ago

7 0

-b/2a is the formula to find the vertex of a parabola. If one of the intercepts is at (-b/2a + 3, 0), the other one must be at (-b/2a - 3, 0), since the two x-intercepts have to be the same distance from the vertex.