Answer: 864
Step-by-step explanation:
mulitiply all
Let unknown integer be n.
So then your sentence would translate to 3n² + n = 2.
If you need to solve for n then we can move 2 to left side by subtract both sides by 2:
3n² + n - 2 = 0
Now you can factor:
3n² + 3n -2n - 2 = 0
3n( n + 1 ) - 2( n + 1 ) = 0
( 3n - 2 )( n + 1 ) = 0
3n - 2 = 0 OR n + 1 = 0
3n = 2 OR n = -1
n = 2/3 OR n = -1
Final answer: n = 2/3 OR n = -1
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Answer:
3/2
Step-by-step explanation:
Given the equation 3/2(4x-2)-3x = 5-(x+2)
Open the parenthesis
3/2(4x) - 3/2(2) -3x = 5-x-2
6x-3-3x = 3-x
3x-3 = 3-x
Collect like terms
3x+x = 3+3
4x = 6
Divide both sides by
4x/4 = 6/4
x = 3/2
Hence the value of x is 3/2
For this case we have to by definition, if two lines are perpendicular then the product of its slopes is -1.
That is to say:
![m_ {1} * m_ {2} = - 1](https://tex.z-dn.net/?f=m_%20%7B1%7D%20%2A%20m_%20%7B2%7D%20%3D%20-%201)
We have the following equation:
![y = -2x + 8](https://tex.z-dn.net/?f=y%20%3D%20-2x%20%2B%208)
So:
![m_ {1} = - 2](https://tex.z-dn.net/?f=m_%20%7B1%7D%20%3D%20-%202)
Thus:
![m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {- 2}\\m = \frac {1}{2}](https://tex.z-dn.net/?f=m_%20%7B2%7D%20%3D%20%5Cfrac%20%7B-1%7D%20%7Bm_%20%7B1%7D%7D%5C%5Cm_%20%7B2%7D%20%3D%20%5Cfrac%20%7B-1%7D%20%7B-%202%7D%5C%5Cm%20%3D%20%5Cfrac%20%7B1%7D%7B2%7D)
Thus, a line perpendicular to the given line must have slope ![m = \frac {1} {2}.](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%20%7B1%7D%20%7B2%7D.)
Option A:
![x + 2y = 8\\2y = -x + 8\\y = - \frac {1} {2} x + 4](https://tex.z-dn.net/?f=x%20%2B%202y%20%3D%208%5C%5C2y%20%3D%20-x%20%2B%208%5C%5Cy%20%3D%20-%20%5Cfrac%20%7B1%7D%20%7B2%7D%20x%20%2B%204)
It is not perpendicular!
Option B:
![x-2y = 6\\2y = x-6\\y = \frac {1} {2} x-3](https://tex.z-dn.net/?f=x-2y%20%3D%206%5C%5C2y%20%3D%20x-6%5C%5Cy%20%3D%20%5Cfrac%20%7B1%7D%20%7B2%7D%20x-3)
If it is perpendicular!
Option C:
![2x + y = 4\\y = -2x + 4](https://tex.z-dn.net/?f=2x%20%2B%20y%20%3D%204%5C%5Cy%20%3D%20-2x%20%2B%204)
It is not perpendicular!
Option D:
![2x-y = 1\\y = 2x-1](https://tex.z-dn.net/?f=2x-y%20%3D%201%5C%5Cy%20%3D%202x-1)
It is not perpendicular!
The correct option is option B
ANswer:
Option B