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Romashka [77]
3 years ago
13

PLEASE HELP

Physics
2 answers:
igomit [66]3 years ago
6 0

Answer:

c

Explanation:

Tamiku [17]3 years ago
5 0
C accelerate more quickly
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You want to race a hoop, I_{hoop} = MR^2I hoop =MR 2 , a solid sphere, I_{solid sphere} = \frac{2}{5}MR^2I solidsphere = 5 2 MR
Veseljchak [2.6K]

Answer:

The fastest object is the sphere, so it is the winner

Explanation:

To know which object will arrive faster down, let's look for the velocity of the center of mass of each object. Let's use the concept of mechanical energy

Highest point

      Em₀ = U = mg y

       

Lowest point

     Em_{f}= K = K_{rot} + K_{cm} = ½ I w² + ½ m v_{cm}²

Angular velocity is related to linear velocity.

       v = w r

       w = v / r

        Em_{f} = ½ I v_{cm}²/r² + ½ m v_{cm}²

        Em_{f} = ½ (I / r² + m) v_{cm}²

Energy is conserved

      Em₀ =  Em_{f}

      mg y = ½ (I / r² + m) v_{cm}²

      v_{cm} = √2 g y / (I / mr² +1)

With this expression we can know which object arrives as a higher speed, therefore invests less time and is the winner. Let's calculate the speed of the center of mass of each

Ring

       I = m r²

      v_{cm} = √ (2 g y / (m r² / mr² + 1))

      v_{cm} = √ (2gy 1/2)

      v_{cm} = (√ 2gy) 0.707

Solid sphere

      I = 2/5 m r²

     v_{cm} = √ (2gy / (2/5 m r² / mr² + 1)

     v_{cm} = √ (2gy / (7/5))

     v_{cm} = √ (2gy 5/7)

     v_{cm} = (√ 2gy) 0.845

Cylinder

      I = ½ m r²

      v_{cm} = √ (2gy / ½ mr² / mr² + 1)

      v_{cm} = √ (2gy / (3/2))

      v_{cm} = √ (2g y 2/3)

      v_{cm} = (√ 2gy) 0.816

The fastest object is the sphere, so it is the winner when descending the ramp

4 0
3 years ago
A tow truck drags a stalled car along a road. The chain makes an angle of 30???? with the road and the tension in the chain is 1
My name is Ann [436]

Answer: work = 1,305kJ

Explanation:

angle= 30°

force= 1,500N

distance= 1,000m

The formula for work is : Work= force x distance, however there is an angle of 30° between the direction of force applied and the direction of motion, therefore force must be decomposed to its value on the horizontal axis which is the direction of motion by using the cosine of the very angle.

W= F×cos(α)×D

W= 1,500×cos (30)×1,000

W= 1,305kJ ( kilojoules)

3 0
4 years ago
Neglecting air resistance, what maximum height will be reached by an arrow launched straight upward with an initial speed of 35
tankabanditka [31]
The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.

The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)

Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
3 0
3 years ago
A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an
Dominik [7]

Answer:

position as a function of time is y = 0.05 × cos(9.9)t

Explanation:

given data

mass = 5 kg

length = 10 cm = 0.1 m

displaced = 5 cm

to find out

position as a function of time

solution

we will apply here equilibrium that is

mass × g = k × length

put here value and find k

k = \frac{5*9.8}{.01}

k = 490 N/m

and ω is

ω = \sqrt{\frac{k}{m} }

ω = \sqrt{\frac{490}{5} }

ω = 9.9

so here position w.r.t  time is

y = 0.05 × cosωt

y = 0.05 × cos(9.9)t

so position as a function of time is y = 0.05 × cos(9.9)t

8 0
3 years ago
What is the formular for force​
goblinko [34]

Answer:

f=m*a

Explanation:

The formula for force says force is equal to mass (m) multiplied by acceleration (a)

5 0
3 years ago
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