Question

A 900 kg car runs into a 70 kg deer at 28 m/s. If the car transfers all of its momentum to the deer, how fast does the deer go flying away?

Answer 1

Answer:

Mc = 900 Kg

Uc = 28 ms^-1

Md = 70 Kg

Ud = 0

We want Vd

Vc = Vd

This situation is elastic momentum

$m _{c}u _{c}+ m _{d}u _{d} = m _{c}v _{c} + m _ dv _{d} \\ (900 \times 28) + (70 \times 0) = (900 \times v _{d} ) + (70 \times v _{d}) \\ 25200 = (900 + 70)v _{d} \\ 25200 = 970v _{d} \\ v _{d} = \frac{25200}{970} \\ v _{d} = 26 \: m {s}^{ - 1}$