<span>To neutralize the charge of 1.0g of electrons?</span>
The net torque exerted by the children on the branch of the tree is 1382 N-m.
The torque exert by the kids is calculated as
T= 45.6*9.8*1.28*cos27.5°+36*9.8*(2.25-1.28)cos27.5°
T=1382 N-m
Hence, The net torque exerted by the children on the branch of the tree is 1382 N-m.
Conductive current is the answer I d k
Answer: 347 bar
Explanation:1) Data:
n = 2520 moles
T = 27 + 273.15 = 298.15 K
V = 180 liter
p = ?
2) Formula
Ideal gas equation: pV = nRT
3) Solution:
p = nRT/V = 2520 mol × 0.0821 atm×liter/K×mol ×298.15K / 180 liter = 342.7 atm
Conversion: 342.7 atm × 1,01325 bar / atm = 347 bar
Answer:
Fscos63
Explanation:
Given that a horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?
Taking the moment from the pivot point P, that means the moment at point p = 0
Then, if we consider the weight mg of the pole, according to the principle of equilibrium : sum of the upward forces equal to the sum of the downward forces.
Therefore, mg = Fsinø ....... (1)
Also, taking moment at point P
Let the length of the pole = s
The length of the weight of the pole = 1/2 S
Fscosø = mgs/2
The distance s will cancel out
2Fcosø = mg ...... (3)
Substitute mg in equation 1 into equation 3
2fcosø = fsinø
F will cancel out
Tanø = 2
Ø = tan^-1(2)
Ø = 63.4 degree
The moment of force F about pivot point P will be
Moment = force × distance
Moment = Fcos63 × S
Moment = Fscos63