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Vilka [71]
3 years ago
15

Other than nuclear power plants and nuclear weapons, are there any other uses for fission?​

Physics
1 answer:
Elodia [21]3 years ago
7 0

Answers

The first power station to produce electricity by using heat from the splitting of uranium atoms began operating in the 1950s. · The applications of nuclear technology 

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Diano4ka-milaya [45]
The answer would be B.

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3 years ago
The teacher measured the maximum height and the minimum height of the plastic duck above the screen as the wave passed. The teac
fenix001 [56]

The teacher measured the maximum height and the minimum height of ...

5 days ago — ... screen as the wave passed . The teacher repeated his measurements. Table 4 shows the teacher's measurements. Calculate the mean amplitude of the water wave.

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3 years ago
An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the righ
vaieri [72.5K]
The answer is +5 units.
8 0
3 years ago
Vector A→, having magnitude 2.5m, pointing 37∘ south of east and vector B→ having magnitude 3.5m, pointing 20∘ north of east are
ahrayia [7]

Answer:

Magnitude of the resultant vector is R = 6.81 m

Explanation:

Given :

Vector A having magnitude of 2.5 m

Vector A having direction 37 degree south of east.

Vector B having magnitude of 3.5 m

Vector B having direction 20 degree north of east.

Therefore, the angle between the two vectors is, θ = 37+20 = 57 degree

So, the resultant of the two vectors are given by

$ R = \sqrt{A^2+B^2+2AB \cos \theta}$

$ R = \sqrt{2.5^2+3.5^2+2(2.5)(3.5) \cos 57}$

$ R = \sqrt{6.25+12.25+17.5 \times 0.54}$

$ R = \sqrt{46.45}$

R = 6.81 m

3 0
3 years ago
Determine a valid way of finding the wire’s diameter if you know the resistivity of the material, \rho , and can measure the cur
olganol [36]

Answer:

To find the diameter of the wire, when the following are given:

Resistivity of the material (Rho), Current flowing in the conductor, I, Potential difference across the conductor ends, V, and length of the wire/conductor, L.

Using the ohm's law,

Resistance R = (rho*L)/A

R = V/I.

Crossectional area of the wire A = π*square of radius

Radius = sqrt(A/π)

Diameter = Radius/2 = [sqrt(A/π)]

Making A the subject of the formular

A = (rho* L* I)V.

From the result of A, Diameter can be determined using

Diameter = [sqrt(A/π)]/2. π is a constant with the value 22/7

Explanation:

Error and uncertainty can be measured varying the value of the parameters used and calculating different values of the diameters. Compare the values using standard deviation

7 0
3 years ago
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