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marysya [2.9K]
3 years ago
14

A 13 foot ladder is leaning against a wall. If the point where the ladder meets the wall is 12 feet above the ground, how far fr

om the base of the wall is the ladder

Mathematics
2 answers:
pashok25 [27]3 years ago
7 0


5 feet bc...

12^2 + B^2 = 13^2

Klio2033 [76]3 years ago
5 0

Answer:

The distance of  the base of the wall to the ladder is 5 Feet .

Step-by-step explanation:

As given

A 13 foot ladder is leaning against a wall.

If the point where the ladder meets the wall is 12 feet above the ground.

As shown in the figure given below.

Now by using the pythagorean theorem

Hypotenuse² = Perpendicular² + Base²

AB² = AC² + BC²

As

AB = 13 foot

AC = 12 foot

Put in the above

13² = 12² + BC²

169 = 144 + BC²

BC² = 169 - 144

BC = \sqrt{25}

BC = 5 Feet

Therefore the distance of  the base of the wall to the ladder is 5 Feet .



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Solve the following equation for H. Be sure to take into account whether a letter is
MrMuchimi

Answer:

H=n-8

Step-by-step explanation:

8+H=n

\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}

8+H-8=n-8

Simplify

H=n-8

7 0
3 years ago
**A rock dropped from a 100 foot tower.
mars1129 [50]

Answer:

2.83 s

Step-by-step explanation:

We are given that

h(t)=-16t^2+10t+100

When a rock reached the ground then h(t)=0

-16t^2+10t+100=0

16t^2-10t-100=0

Using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

t=\frac{10\pm\sqrt{(-10)^2-4\times 16\times (-100)}}{2(16)}

t=\frac{10\pm\sqrt{100+6400}}{32}

t=\frac{10+\sqrt{6500}}{32}=2.83

t=\frac{10-\sqrt{6500}}{32}=-2.2

Time cannot be negative .Therefore, negative value of t can not be possible.

Hence, the rock takes 2.83 sec to reach the ground.

8 0
3 years ago
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
Using the formula for initial velocity h=-16t2+VT the height of any object can be found by the time, Annalee serves a volleyball
Marrrta [24]

The ball will hit the ground at 0.125 seconds

<h3>Quadratic function</h3>

The equation of the function is a quadratic function, and the function is given as:

h = -16t^2 + 2t

When the ball hits the ground, the value of h is 0.

So, the equation of the function becomes

-16t^2 + 2t = 0

Subtract 2t from both sides of the equation

-16t^2 =- 2t

Divide both sides by -2t

8t =1

Divide both sides by 8

t =0.125

Hence, the ball will hit the ground at 0.125 seconds

Read more about quadratic functions at:

brainly.com/question/11631534

5 0
2 years ago
The personnel files of all eight employees at the Pawnee location of Acme Carpet Cleaners Inc. revealed that during the last six
irina [24]

Answer:

a) For Pawnee:

Range = 11, Mean = 3.13, Mean deviation = 2.44

For Chickpee:

Range =  7, Mean = 4.25, Mean deviation = 1.59

b) Pawnee Location has fewer lost days.

c) variation of the Chickpee is less than Pawnee location

Step-by-step explanation:

Data given:

For Pawnee:

3 1 0 0 2 11 5 3

Max = 11

Min = 0

Range = Max - Min

Range = 11-0 = 11

Range = 11

For Chickpee:

3 6 8 4 4 5 3 1

Max = 8

Min = 1

Range = Max - Min

Range = 8 - 1

Range = 7

For mean of Pawnee:

Mean = (3 + 1 + 0 + 0 + 2 + 11 + 5 + 3)/8

Mean = 25/8

Mean = 3.125

For mean deviation, we find the difference from the mean of each point.

Note: all the negative values will be taken as 0.

Differences from the mean of each point =

(3-3.13)=0.13, (1-3.31) = 2.13 ,

(0-3.13)=0, (0-3.13)=3.13,

(2-3.13)=1.13, (11-3.13)=7.87,

(5-3.13)=1.87, (3-3.13)=0.13

So, our differences are:

(0.13, 2.13, 0, 3.13, 1.13, 7.87, 1.87, 0.13 )

Mean deviation =  Sum of all differences/8

Mean deviation = (0.13+2.13+3.13+3.13+ 1.13+ 7.87+ 1.87+ 0.13)/8

Mean deviation = 2.44

For mean of Chickpee:

Mean = (3+6+8+4+4+5+3+1)/8

Mean = 34/8

Mean = 4.25

Similarly, we need to find mean deviation for Chickpee, for that we need to find the differences first as done above for Pawnee.

Note: all the negative values will be taken as 0

Differences from the mean:

(3-4.25) = 1.25, (6-4.25) =1.75,

(8-4.25) = 3.75, (4-4.25)=0.25,

(4-4.25)=0.25, (5-4.25)= 0.75,

(3-4.25)=1.25, (1-4.25) =3.25

So, the differences are:

Differences = (1.25,1.75,3.75,0.25,0.25,0.75,1.25,3.25)

Mean deviation = (1.25+ 1.75+ 3.75+ 0.25+ 0.25+ 0.75+ 1.25+ 3.25)/8

Mean deviation = 1.59

b) which location has fewer lost days:

This can be found out by the total number of days of Pawnee and chickpee.

Pawnee = Sum of values = (3 + 1 + 0 + 0 + 2 + 11 + 5 + 3) = 25 days

Chickpee = Sum of values = (3+6+8+4+4+5+3+1) = 34 days

Hence, Pawnee Location has fewer lost days.

C) which location has less variation?

Formula for variation = ∑(\frac{x^{2} }{8}) - (mean^{2})

where x = values of the set.

For Pawnee:

mean^{2} = 3.13^{2} = 9.8

Sum of square of all the data points of Pawnee = 169

Variation = 169/8 - 98 = 11.325

Similarly,

For Chickpee:

mean^{2}  = 4.25^{2} = 18.06

Sum of square of all the data points of Chickpee = 176

Variation = 176/8 - 18.06

Variation = 22-18.06

Variation = 4

Hence, variation of the Chickpee is less than Pawnee location

8 0
3 years ago
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