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3 years ago

Which expression is equivalent to 5y + 2y + 6x + 2y - x

1 answer:

4 0

Im pretty sure that would be 9y+5x
you would pair up your pairs so take 5y plus 2y plus 2y giving you 9y then you would tale 6x plus -x giving you 5x then you put them together which would be
9y+5x
hope this helps

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Solve: 9x - 3 = 729

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Answer:

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Step-by-step explanation:

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3 years ago

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AURORKA [14]

Answer:

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Step-by-step explanation:

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2 years ago

Find the value of y for which a the values of 5y+3 and 36–y are equal<br><br> plzzzz

Travka [436]

Answer:

11/2

Step-by-step explanation:

5y+3=36-y

1) Subtract 3 from both sides:

5y=33-y

2) Add y to both sides:

6y=33

3) divide both sides by 6:

y=33/6

4) Simplify the fraction:

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3 years ago

I’m not good with geometry please help

jasenka [17]

Answer:

The value of t is 41

Step-by-step explanation:

<em>The figure is 5 sided polygon.</em>

The sum of interior angles of 'n' sided polygon is given by,

= $180(n-2) degrees$

here, n=5,

thus, $180(5-2) = 180(3) = 540 degrees$

All the given angles have linear pair in the polygon.

$(180-2t)+(180-3t)+(180-42)+(180-52)+(180-61) = 540$

$5t = 205$

Thus, t = 41

8 0

3 years ago

The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

$A=P(1+r)^x$

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

$1000=P(1+r)^0\implies P = 1000$

A = 1900 when x = 1,

$1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9$

Thus, the required function that represents the population after x days,

$A=1900(1+0.9)^x=1900(1.9)^x$

If x = 4,

The number of mosquito after 4 days,

$A=1900(1.9)^4 = 24760.99\approx 24761$

If A = 60,000,

$60000 = 1900(1.9)^x$

$\frac{600}{19}=1.9^x$

Taking log both sides,

$\log(\frac{600}{19})=x\log 1.9$

$\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4$

Thus, there will 60,000 mosquitoes after 5 days.

6 0

3 years ago