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3 years ago

12

TRUE OR FALSE!!! PICTURE IS SHOWN

1 answer:

schepotkina [342]3 years ago

5 0

False

distance = square root [(x2−x1)^2+(y2−y1)^2]

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A Chi square test has been conducted to assess the relationship between marital status and church attendance. The obtained Chi s

Margarita [4]

Answer: a. reject the null hypothesis, church attendance and marital status are dependent

Step-by-step explanation:

If the obtained chi-square value is greater than the critical chi square value then we reject the null hypothesis.

Given : A Chi square test has been conducted to assess the relationship between marital status and church attendance. The obtained Chi square is 23.45 and the critical Chi square is 9.488.

Null hypothesis : There is no relationship between the variables.

Alternative hypothesis : There is a relationship between the variables.

Here we can see that the obtained chi-square (23.45) value is greater than the critical chi square value (9.488) , then we have to reject the null hypothesis.

So the correct answer is reject the null hypothesis, church attendance and marital status are dependent.

3 0

3 years ago

Can someone help me in this question

Masja [62]

Answer:

try

Simplify the expression.

15x-17 or 2x-6

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t

GrogVix [38]

<u>QUESTION 1</u>

The given system of equation is

$y=x-6...eqn1$

and

$3x+2y=8...eqn2$

Let us substitute equation (1) into equation (2) to get,

$3x+2(x-6)=8$

We expand the bracket to get,

$3x+2x-12=8$

We simplify to get.

$5x-12=8$

We group like terms to get

$5x=8+12$

$\Rightarrow 5x=20$

$\Rightarrow x=4$

We now substitute $x=4$ in to equation (1) to obtain,

$y=4-6=-2$

The correct answer is option A.

<u>QUESTION 2</u>

The given system of equations is

$y-x=9...eqn1$

and

$10+2x=-2y...eqn2$

We make y the subject in equation (2) to get,

$y=-x-5..eqn3$

We put equation (3) into equation (1) to obtain,

$-x-5-x=9$

We group like terms to get,

$-x-x=9+5$

This implies that,

$-2x=14$

We divide through by $-2$ to get,

$x=-7$

Hence the x-coordinate is $-7$

<u>QUESTION 3</u>

The given system is

$y=3x-1..eqn1$

and

$x-y=-9...eqn2$

We make $x$ the subject in equation (2) to get,

$x=y-9...eqn3$

We put equation (3) into equation (1) to obtain,

$y=3(y-9)-1$

We expand the bracket to get,

$y=3y-27-1$

Group like terms to get,

$y-3y=-27-1$

We simplify to get;

$-2y=-28$

This implies that,

$y=14$

Therefore the y-coordinate is 14.

4 0

4 years ago

Read 2 more answers

I think of a number, add 8 to it and the result is 14. Find the number

Leya [2.2K]

Answer:

6

Step-by-step explanation:

The equation for this would be:

n+8=14, since we are adding 8 to a number and getting 14

To solve, isolate the variable n, by subtracting 8 from both sides

n+8=14

n+8-8=14-8

n=6

The number is 6

3 0

3 years ago

Read 2 more answers

If I roll a 6 sided dice and then flip a coin,

lina2011 [118]

Answer:

1/12

Step-by-step explanation:

5 0

3 years ago