A salt truck drops 39 kilograms of salt per minute. How many grams of salt does the truck drop per second?

You are painting the outside of a 28-foot fence that goes around a square garden. There are 4 equal sections. You have painted 1

Arisa [49]

Well, to figure this out, you would have to divide 28 by 4, since there are four sections. That is 7. 7 divided by 2 is 3.5, so you would have completed 3.5 feet of the fence.

7 0

3 years ago

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Help please! Thank you:)

Masja [62]

Answer:

what kind of math is that?

Step-by-step explanation:

7 0

3 years ago

How to solve ( 3 × n ) + 4 = 32 ÷ 2

Bas_tet [7]

(3 * n) +4 = 16
(3 * n) = 12
n = 4

6 0

3 years ago

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Recent homebuyers from a local developer allege that 30% of the houses this developer constructs have some major defect that wil

umka21 [38]

Answer:

3.54% probability of observing at most two defective homes out of a random sample of 20

Step-by-step explanation:

For each house that this developer constructs, there are only two possible outcomes. Either there are some major defect that will require substantial repairs, or there is not. The probability of a house having some major defect that will require substantial repairs is independent of other houses. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

30% of the houses this developer constructs have some major defect that will require substantial repairs.

This means that $p = 0.3$

If the allegation is correct, what is the probability of observing at most two defective homes out of a random sample of 20

This is $P(X \leq 2)$ when n = 20. So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.3)^{0}.(0.7)^{20} = 0.0008$

$P(X = 1) = C_{20,1}.(0.3)^{1}.(0.7)^{19} = 0.0068$

$P(X = 2) = C_{20,2}.(0.3)^{2}.(0.7)^{18} = 0.0278$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0008 + 0.0068 + 0.0278 = 0.0354$

3.54% probability of observing at most two defective homes out of a random sample of 20

5 0

3 years ago

Which part of the roman republic was in charge of judging trials

aleksley [76]

Answer:

Praetors

Step-by-step explanation:

The praetors administered civil law and commanded provincial armies, and, eventually, began to act as chief judges over the courts.Praetors were part of the judicial branch, they were elected yearly by the people of Rome, and acted as judges.

3 0

3 years ago