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3 years ago

What is 8.478 in expanded form?

2 answers:

nataly862011 [7]3 years ago

7 0

8+0.4+0.07+0.008 you basically separate the numbers starting with the largest working down to the smallest.

i hope i helped

Wittaler [7]3 years ago

7 0

Expanded form is the representation of a number with factors, exponents or words and separated into individual place values and decimal places that can form a mathematical expression. 8 + 0.4+ 0.07+ 0.008

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tamaranim1 [39]

Answer:

Step-by-step explanation:

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3 years ago

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Part A: Explain why x = 5 makes 4x - 1 3 19 true but not 4x - 1 19

Olenka [21]

Answer:

Part A: Explain why x = 5 makes 4x - 1 ≤ 19 true but not 4x - 1 < 19

Part B: x=9

Step-by-step explanation:

Part A: Because the first one is less than or equal to 19 and the other is just less than.

x = 5

TRUE: 4x - 1 ≤ 19 = 20-1 ≤ 19 = 19 ≤ 19

19 is less than or equal to 19 so its true

FALSE: 4x - 1 < 19 = 19 < 19

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Part B:

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To check we can plug it back in

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3 years ago

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4 years ago

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For the equation x2 = a, describe the values of a that will result in two real solutions, one real solution, and no real solutio

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The equation given is $x^{2} =a$ where a is some number.
We can solve for x by taking the square root of both sides.

$x=plusminus \sqrt{a}$

Now let's think through what happens for various values of a.

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If a = 0 there is only one solution. That is because $x^{2} =0$ and $x= \sqrt{0}$ . Zero is neither positive nor negative and it has only one root which is 0 itself. So in this case there is only one solution and it is 0.

NO (REAL) SOLUTIONS
If a is negative we would be taking the square root of a negative number. There is no (real) number that when multiplied by itself gives a negative number. Take for example $x^{2} =-49$ which gives us $x= \sqrt{-49}$ . The square root of -49 is not 7 because (7)(7)=49 which is positive. The square root of -49 is not -7 because (-7)(-7)=49 which is also positive. There is no real number that gives -49 when multiplied by itself. I say "real" numbers because there do exist imaginary/complex numbers but because of the way the questions was asked I imagine you may not know about these yet.

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