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zhenek [66]
3 years ago
15

In the figure below, angle ABD measure 41°. what is the measure of angle ABC?

Mathematics
1 answer:
Grace [21]3 years ago
3 0
Can you post the figure please :)
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Solve the proportion: 144/a = 9/4<br>a=?<br>​
marin [14]

Step-by-step explanation:

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7 0
2 years ago
Describe the following variation: y/x2=5
Firdavs [7]
We are asked to describe the variation \displaystyle{ \frac{y}{x^2}=5, 

that is y=5x^2

for x≠0, in which case x=y=0, we distinguish the following intervals:

I   = (-infinity, -1]
II  = (-1, 0)
III = (0, 1)
III = [1, infinity)

Case I, consider the cases (examples)   x= -5, and x= -6

5(-6)^2\ \textgreater \ 5(-5)^2, so we can conclude that the greater the x, the smaller the y.

Case II, consider x= -1/2 < x=-1/3

5(-\frac{1}{2})^2= \frac{5}{4}\\\\ 5(-\frac{1}{3})^2= \frac{5}{9}\\\\\frac{5}{9}\ \textless \  \frac{5}{4}

thus, the greater the x, the smaller the y.


Case III, consider the cases (examples)   x= 5, and x= 6

5(6)^2\ \textgreater \ 5(5)^2, so we can conclude that the greater the x, the greater the y.

Case III, consider x= 1/3 < x=1/2

5(\frac{1}{2})^2= \frac{5}{4}\\\\ 5(\frac{1}{3})^2= \frac{5}{9}\\\\\frac{5}{9}\ \textless \ \frac{5}{4}

thus, the greater the x, the greater the y.


Conclusion:

y=0 only if x is 0. Otherwise y>0 always:

for x<0,   x and y are inversely proportional

for x>0,   x and y are directly proportional.


Remark, an other possible consideration in cases could be x<0 and x>0 only.


Remark, 
another approach is considering the graph of y=5x^2, which is a parabola, with the vertex at (0, 0) opening upwards.

From the graph we can find the same conclusion. That is we can see that the farer we get away from the y-axis, in both direction, the larger the values of y become.

4 0
3 years ago
Oliver wants to buy a new TV, The price was $985. When he goes to the store a
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344.75 I did the math lol not that hard tbh
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2 years ago
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1. 7,3
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Find the cost per roll if a bag of five lunch rolls is $2.50.
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<h3><u><em>My friends the answer is:</em></u></h3><h3><u><em>If 1 lunch =$2.50 </em></u></h3><h3><u><em> 2 lunches = $5.00 (2.50x2) </em></u></h3><h3><u><em> 3 lunches =$7.50 </em></u></h3><h3><u><em> 4 lunches =$10.00 </em></u></h3><h3><u><em> 5 lunches= $12.50 </em></u></h3><h3><u><em> Just add $2.50</em></u></h3>
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3 years ago
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