All categories

3 years ago

Which of the following best describes T in the general formula for an exponential function, which is shown below?

Mathematics

1 answer:

Marina86 [1]3 years ago

4 0

Answer:

A. Time

Step-by-step explanation:

The general formula for an exponential function is shown below:

$F(t) = Ao.b^{kt}$

where,

Ao = Initial amount

b = growth factor i.e come (1 + r)

r = growth rate

k = Constant

T = Time

Therefore the T describes the time

Hence, the first option is correct

To determine any of the above variable we simply used the above formula so the chances of thh correct answer could be high

You might be interested in

Which of the following is equivalent to X2 - 8x - 7 = 0?

I am Lyosha [343]

Answer:

Part 1) (the missing steps in the explanation)

Part 3) (8, 4); The vertex represents the maximum profit

Part 4) x = 3.58, 0.42

Part 5) x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made

Part 6) 2(x − 7)2 + 118; x = $7

Part 7) The maximum height of the puck is 4 feet. −(x − 4)^2 + 6

Part 8) (x + 3)^2 − 4

Part 9) 2(x − 1)^2 = 4

Part 10) 8(x − 4)^2 + 592

Step-by-step explanation:

3 0

3 years ago

The question is on the picture

Aleonysh [2.5K]

Answer:

The third one is the correct answer!

Because:

there are 2 plots on 39
there is 1 plot on 42
1 plot on 44
1 plot on 45
1 plot on 46
3 plots on 48
and 1 plot on 51

No more no less.

Hope this helped!

6 0

2 years ago

In the problem • N = 1, N must be

Basile [38]

The answer is 1 by multiplying by itself

6 0

3 years ago

The state medical school has discovered a new test for tuberculosis. (If the test indicates a person has tuberculosis, the

Inessa [10]

The probability according to the given scenario is:

(a) 0.0395

(b) 0.95

(c) 0.076

The given values are:

$P(B/A) = 0.79$
$P(A) = 0.05$

(a)

The probability that the b/w has tuberculosis as well as having (+) test will be:

→ $P(A \cap B) = P(B/A).P(A)$

By substituting the values, we get

→ $= 0.79\times 0.05$

→ $= 0.0395$

(b)

The probability that a person does not have tuberculosis will be:

→ $P(A') = 1-P(A)$

→ $=1-0.05$

→ $= 0.95$

(c)

The person does not have tuberculosis as well as have a (+) test, the probability will be:

→ $P(A' \cap B) = P(A').P(B/A')$

→ $= 0.95\times 0.08$

→ $= 0.076$

Learn more:

brainly.com/question/14816227

8 0

1 year ago

Eric and Joshua are playing ping pong and pool. Joshua believes he has a good chance of beating Eric in at least one of the game

Sunny_sXe [5.5K]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Eric and Joshua are playing ping pong and pool. Joshua believes he has a good chance of beating Eric in at least one of the games. The probability Joshua beats Eric in ping pong is 0.48. The probability Joshua beats Eric in pool is 0.46. Joshua is willing to assume the probability of Eric winning a game of ping pong is independent of him winning a game of pool.

Find the probability:

The probability that Joshua beats Eric in ping pong AND pool?

The probability that Joshua beats Eric in ping pong OR pool?

Answer:

P(pp & pool) = 22%

There is 22% probability that Joshua beats Eric in ping pong AND pool.

P(pp OR pool) = 50%

There is 50% probability that Joshua beats Eric in ping pong OR pool.

Step-by-step explanation:

The probability Joshua beats Eric in ping pong is given by

P(pp) = 0.48

The probability Joshua beats Eric in pool is given by

P(pool) = 0.46

The probability that Joshua beats Eric in ping pong AND pool is given by

P(pp & pool) = P(pp)×P(pool)

P(pp & pool) = 0.48×0.46

P(pp & pool) = 0.22

P(pp & pool) = 22%

Therefore, there is 22% probability that Joshua beats Eric in ping pong AND pool.

The probability that Joshua beats Eric in ping pong OR pool is given by

P(pp OR pool) = P(pp)×0.52 + P(pool)×0.54

Where 0.52 is the probability that Eric beats Joshua in the ping pong match (1 - 0.48 = 0.52)

Where 0.54 is the probability that Eric beats Joshua in the pool match (1 - 0.46 = 0.54)

P(pp OR pool) = 0.48×0.52 + 0.46×0.54

P(pp OR pool) = 0.25 + 0.25

P(pp OR pool) = 0.50

P(pp OR pool) = 50%

Therefore, there is 50% probability that Joshua beats Eric in ping pong OR pool.

6 0

3 years ago