Question

What are the solutions ?0%2B%203x" id="TexFormula1" title="7x ^{2} + 10x - 3 = x ^{2} + 3x" alt="7x ^{2} + 10x - 3 = x ^{2} + 3x" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$x = \frac{ - 3}{2} \: or \: \frac{1}{3}$

Step-by-step explanation:

$7 {x}^{2} + 10x - 3 = {x}^{2} + 3x$

$= > 7 {x}^{2} - {x}^{2} + 10x - 3x -3 = 0$

$= > 6 {x}^{2} + 7x - 3 = 0$

$= > 6 {x}^{2} + 9x - 2x - 3 = 0$

$= > 3x(2x + 3) - 1(2x + 3) = 0$

$= > (2x + 3)(3x - 1) = 0$

Here x will have 2 values.

1) $2x + 3 = 0$

$= > 2x = - 3$

$= > x = \frac{ - 3}{2}$

2)$3x - 1 = 0$

$= > 3x = 1$

$= > x = \frac{1}{3}$