Answer:
Statement D is false
D. Java class libraries are not portable = FALSE
Explanation:
Because java class library are portable and JVM (java virtual machine) makes java class library and other java codes portable and platform independent and JVM act as a OS or imaginary CPU for that code.
Answer:
There are two ways to print 1 to 1000
- Using Loops.
- Using Recursion.
Explanation:
Using loops
for(int i=1;i<=1000;i++)
{
cout<<i<<" ";
}
Using recursion
Remember you can implement recursion using a function only.
void print(int n)
{
if(n==0)
return;
print(n-1);
cout<<n<<" "';
}
you should pass 1000 as an argument to the function print.
Answer:
def rec_dig_sum( num ):
num_list = [ digit for digit in str(num)]
total = 0
for x in num_list:
total += x
return total
def dict_of_rec_dig_sums(low, high):
mydict = dict()
for number in the range(low, high+1):
mydict[rec_dig_sum(number)] = number
return mydict
Explanation:
The python program defines two functions, "rec_dig_sum" and "dict_of_rec_dig_sums". The former accepts a number and returns the sum of the digits of the number while the latter accepts a low and high number range.
The program returns a dictionary with the recursive sum as the keys and the number count as the values.
Add the following constants in the class definition, before the main method:
private final static float START_COST = 1.5f;
private final static float HIGH_TARIFF = 0.5f;
private final static float LOW_TARIFF = 0.25f;
private final static int FIXED_MINS = 2;
private final static int HIGH_TARIFF_MINS = 10;
Then add this to the main method you already had:
float price = START_COST;
if (x > FIXED_MINS) {
if (x <= HIGH_TARIFF_MINS) {
price += HIGH_TARIFF*(x-FIXED_MINS);
}
else {
price += HIGH_TARIFF*(HIGH_TARIFF_MINS-FIXED_MINS)
+ LOW_TARIFF*(x-HIGH_TARIFF_MINS);
}
}
System.out.printf("A %d minute call costs %.2f", x, price);
