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Andrei [34K]
3 years ago
13

Does anyone else realize how the only tutor is for math never any other subjects?​

Computers and Technology
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

yes I do and I wonder why ??

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Write Java code that creates an array of n integers myArray, by taking n integers from the user with duplications, and do the fo
skad [1K]

Answer:

this should be what you need

Explanation:

import java.util.*;

public class ABC{

 public static void main(String[] args) {

   int n;

   //create scanner object

   Scanner sc = new Scanner(System.in);

   //ask for size of array

   System.out.print("Enter the size of array (n): ");

   //read the input

   n = sc.nextInt();

   //create an array of n length

   int [] myArray = new int[n];

   //ask user for array elements

   System.out.printf("Enter %d integers: ", n);

   //read array elements

   for(int i =0 ;i <5; i++)

     myArray[i] = sc.nextInt();

   

   //print the elements if myArray

   System.out.print("1 - The values of myArray are: [");

   for(int i =0 ; i < n; i++){

     System.out.print(myArray[i]);

     if(i < n-1)

       System.out.print(", ");

   }

   System.out.print("]\n");

   //calculate mean and sum of myArray elements

   int sum = 0;

   double mean = 0;

   for(int i = 0; i < n; i++)

     sum += myArray[i];

   

   mean = (sum*1.0)/n;

   //print the sum and mean of myArray

   System.out.printf("2 - The sum is: %d. The mean is: %.1f\n", sum, mean);

     

   //create an arraylist

   ArrayList<Integer> myArrayList = new ArrayList<Integer>();

   //copy the value of myArray to an arraylist without duplicates

   for(int i = 0; i < n; i++){

     if(!myArrayList.contains(myArray[i]))

       myArrayList.add(myArray[i]);

   }

   sum = 0; mean = 0;

   //display the values of myArrayList

   System.out.print("3 - The values of myArrayList are: [");

   for(int i =0 ; i < myArrayList.size(); i++){

     System.out.print(myArrayList.get(i));

     if(i < myArrayList.size()-1)

       System.out.print(", ");

   }

   System.out.print("]\n");

   //calculate sum and mean of myArrayList elements

   for(int i = 0; i < myArrayList.size(); i++)

     sum += myArrayList.get(i);

   mean = (sum*1.0)/myArrayList.size();

   //print the sum and mean of myArrayList

   System.out.printf("4 - The sum is: %d. The mean is: %.2f\n", sum, mean);

 }

}

3 0
3 years ago
Suppose you are an ISP that owns a / 22 IPv4 address block. Can you accommodate requests from six customers who need addresses f
lisabon 2012 [21]

Answer:

It is not possible.

Explanation:

In this example, we need to accommodate 473 computers for six clients that are 473 IP addresses.

For this request just we have /22 IPv4 address blocks, this mean

22 red bits 11111111111111111111110000000000 <--- 10 host bits

We must increase red bits to 25, we need these 3 bits to create 6 sub red, in this case, 2^3 = 8 sub red.

Why did we ask 3 bits? Because if we ask only 2, 2^2 = 4, and we need 6 sub red.

25 red bits 11111111111111111111111110000000 7 host bits

In this case, we need more than 260 computers, but just we have 7 bits, this means.

2^7 = 128 and just one customer needs 260, for that is impossible.

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3 years ago
6.4 Predicting Prices of Used Cars. The file ToyotaCorolla.csv contains data on used cars (Toyota Corolla) on sale during late s
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Answer:

Compare the predictions in terms of the predictors that were used, the magnitude of the difference between the two predictions, and the advantages and disadvantages of the two methods.

Our predictions for the two models were very simmilar. A difference of $32.78 (less than 1% of the total price of the car) is statistically insignificant in this case. Our binned model returned a whole number while the full model returned a more “accurate” price, but ultimately it is a wash. Both models had comparable accuracy, but the full regression seemed to be better trained. If we wanted to use the binned model I would suggest creating smaller bin ranges to prevent underfitting the model. However, when considering the the overall accuracy range and the car sale market both models would be

Explanation:

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A pressure regulator application on his computer or a station nearbye
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True or false a weighted inventory system is often tied into player advancement
alekssr [168]

Answer:tayfana

Explanation:true

7 0
2 years ago
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