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maksim [4K]
3 years ago
10

The diagram represents 6X squared minus 7 X +2 with factor of 2X minus oneWhat is the other factor of 6X squared -7+2?

Mathematics
1 answer:
agasfer [191]3 years ago
3 0

Answer:

(3x - 2)

Step-by-step explanation:

6x² - 7x + 2 can be factored using the trial and error method, the AC method, factoring by grouping, or using the quadratic formula

i will use factoring by grouping to solve

to factor by grouping: we divide the expression into 4 terms. since there are only 3 terms, we need to expand the expression. to do this, we can write 7x as a subtraction.

6x² - 3x - 4x + 2

now that we have 4 terms, we can factor by grouping by dividing the expression in half:

(6x² - 3x) (-4x + 2)

lets look at 6x² - 3x: what GCF do they have in common? both have 3x as a common factor so we will factor out 3x from the expression

3x (2x - 1)

now we take a look at -4x + 2: what GCF do they have in common? we want to have (2x - 1) as a result of the factoring job, so what number gives us that? we would have to get rid of that negative, so lets factor out -2 from the expression:

-2 (2x - 1)

the expression looking like the following:

3x (2x - 1) - 2 (2x - 1)

we can put 3x and -2 into their own factor as we have 2x - 1 as a factor already and there is no need to repeat that

(3x - 2) (2x - 1)

the missing factor is (3x - 2)

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Darnel buys a computer priced at $331. If the sales tax is 5%,how much tax will Darnel pay?
34kurt

Answer:

347.55

Step-by-step explanation:

331 x 0.05 =16.55

16.55 + 331 = 347.55

5 0
2 years ago
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There are 196 countries in the world. How many students must be enrolled in a university to guarantee that there are at least 20
cestrela7 [59]

Answer:

At least 39200 students.

Step-by-step explanation:

Given that there are 196 countries in the world, and each country would have at least 200 students in a university.

For each country to have at least 200 students in the university, then;

Number of students enrolled in the university = number of required students x number of countries

                                      = 200 x 196

                                      = 39200

At least, 39200 students must be enrolled in the university. Provided that the admission procedures are conditioned for the purpose.

3 0
3 years ago
If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm
Juliette [100K]
<span>A midpoint divides a line or a segment into two equal parts. If D is the midpoint of the segment AC and C is the midpoint of segment DB, what is the length of the segment AB, if AC = 3 cm.</span>

 

If D is the midpoint of AC, then AD=DC

If C is the midpoint of DB, then DC=CB

If AC=3cm. then then DC-3/2=1.5

If DC=1.5 then CB is 1.5 also

AB=AC+CB

AB=3+1.5

AB=4.5

5 0
3 years ago
8. Find the slope of the line passing through<br> (4,10) and (8,30)
rjkz [21]
Hbbbbhhhhhhhhhhhhhhhhhhhhhhhhhhbbbb
5 0
3 years ago
CON PROCESOS POR FAVOR
labwork [276]

Answer:

\dfrac{149}{40}

\dfrac{38}{15}

Step-by-step explanation:

(\dfrac{7}{8} + \dfrac{4}{5}) - (\dfrac{9}{20} + \dfrac{-5}{2}) =

= (\dfrac{7}{8} \times \dfrac{5}{5} + \dfrac{4}{5} \times \dfrac{8}{8}) - (\dfrac{9}{20} + \dfrac{-5}{2} \times \dfrac{10}{10})

= (\dfrac{35}{40} + \dfrac{32}{40}) - (\dfrac{9}{20} + \dfrac{-50}{20})

= \dfrac{67}{40} - (-\dfrac{41}{20})

= \dfrac{67}{40} + \dfrac{41}{20} \times \dfrac{2}{2}

= \dfrac{67}{40} + \dfrac{82}{40}

= \dfrac{149}{40}

(-\dfrac{6}{4} + \dfrac{3}{2}) + (\dfrac{6}{5} + \dfrac{4}{3}) =

= (-\dfrac{3}{2} + \dfrac{3}{2})+ (\dfrac{6}{5} \times \dfrac{3}{3} + \dfrac{4}{3} \times \dfrac{5}{5})

= 0 + \dfrac{18}{15} + \dfrac{20}{15}

= \dfrac{38}{15}

4 0
2 years ago
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