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Reil [10]
2 years ago
6

What is the answer if Increase 12% by 30%

Mathematics
2 answers:
rosijanka [135]2 years ago
7 0

Answer:

3.6

Step-by-step explanation:

Percentage increase =

30% × 12 =

30 ÷ 100 × 12 =

30 × 12 ÷ 100 =

360 ÷ 100 =

3.6

mrs_skeptik [129]2 years ago
3 0

Answer:

Introduction. Percent, p%

'Percent (%)' means 'out of one hundred':

p% = p 'out of one hundred',

p% is read p 'percent',

p% = p/100 = p ÷ 100.

30% = 30/100 = 30 ÷ 100 = 0.3.

100% = 100/100 = 100 ÷ 100 = 1.

Increase the number by 30% of its value.

Calculate the New Value

New value =

12 + Percentage increase =

12 + (30% × 12) =

12 + 30% × 12 =

(1 + 30%) × 12 =

(100% + 30%) × 12 =

130% × 12 =

130 ÷ 100 × 12 =

130 × 12 ÷ 100 =

1,560 ÷ 100 =

15.6

Calculate absolute change (actual difference)

Absolute change (actual difference) =

New value - 12 =

15.6 - 12 =

3.6

Step-by-step explanation:

please mark me brainliest!

hope this helps

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What is the area of the shaded part? ​
iVinArrow [24]

Answer:

Step-by-step explanation:

(8x-3)^2-x^2

64x^2-48x+9-x^2

63x^2-48x+9

8 0
2 years ago
. Find the inverse of the function below on the given interval and write it in the form yequalsf Superscript negative 1 Baseline
Elena L [17]

Answer:

The inverse of the function is f^{-1}(x)=\frac{x-5}{3}.

Step-by-step explanation:

The function provided is:

f (x)=3x+5

Let f(x)=y.

Then the value of <em>x</em> is:

y=3x+5\\\\3x=y-5\\\\x=\frac{y-5}{3}

For the inverse of the function, x\rightarrow y.

⇒ f^{-1}(x)=\frac{x-5}{3}

Compute the value of f[f^{-1}(x)] as follows:

f[f^{-1}(x)]=f[\frac{x-5}{3}]

               =3[\frac{x-5}{3}]+5\\\\=x-5+5\\\\=x

Hence proved that f[f^{-1}(x)]=x.

Compute the value of f^{-1}[f(x)] as follows:

f^{-1}[f(x)]=f^{-1}[3x+5]

               =\frac{(3x+5)-5}{3}\\\\=\frac{3x+5-5}{3}\\\\=x

Hence proved that f^{-1}[f(x)]=x.

8 0
2 years ago
The graph of f(x) = 2x + 4 shifts five units to the right when it is replaced with the graph of f(x) = 2x - k. What is the value
DIA [1.3K]
<h2>Answer</h2>

C.) 1

<h2>Explanation </h2>

Remember the rules for shifting functions:

f(x)+b shifts the function b units upward

f(x)-b shifts the function b units downward

f(x+b) shifts the function b units to the left

f(x-b) shifts the function b units to the right

Since we want tho shift f(x)=2^{x+4} 5 units to the right, we are using the rule: f(x-b) shifts the function b units to the right; in other words, we need to subtract 5 units to the input of the function:

f(x)=2^{x+4-5}

f(x)=2^{x-1}

But notice that there is already a negative sign in f(x)=2^{x-k}, so to get f(x)=2^{x-1}, k must be equal to positive 1.

7 0
2 years ago
Read 2 more answers
A/20 + 14/15 = 9/15 <br><br> Can i get some help?
KiRa [710]
Method 1:

\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |multiply\ both\ sides\ by\ 60\\\\60\cdot\dfrac{a}{20}+60\cdot\dfrac{14}{15}=60\cdot\dfrac{9}{15}\\\\3a+4\cdot14=4\cdot9\\\\3a+56=36\ \ \ \ |subtract\ 56\ from\ both\ sides\\\\3a=-20\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=-\frac{20}{3}\to a=-6\frac{2}{3}}

Method 2.

\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |subtract\ \dfrac{14}{15}\ form\ both\ sides\\\\\dfrac{a}{20}=-\dfrac{5}{15}\\\\\dfrac{a}{20}=-\dfrac{1}{3}\ \ \ \ |multiply\ both\ sides\ by\ 20\\\\\boxed{a=-\dfrac{20}{3}\to a=-6\frac{2}{3}}
3 0
3 years ago
Please help me! I need the anwser asap​
sasho [114]
What is the question you are trying to ask
3 0
3 years ago
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