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Ivan
3 years ago
7

A school spent $150 on advertising for a breakfast fundraiser. Each plate of food was sold for $8.00 but cost the school $2.00 t

o prepare. After all expenses were paid, the school raised $2,400 at the fundraiser. Which equation can be used to find x, the number of plates that were sold?
Mathematics
2 answers:
alukav5142 [94]3 years ago
8 0
Cada prato custa US $8,00 na custou US $2,00 para ser feito cada prato ou seja US $6,00 de lucro por prato só fazer 6 ÷ 2400 = 400

Para ter certeza 6.400=2400
Diano4ka-milaya [45]3 years ago
3 0
225 plates were sold.
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An isosceles triangle has angle measures 50°, 50°, and 80°. The side across from the 80° angle is 10 inches long. How long are t
djverab [1.8K]

Answer: The value of other side is 7.8 inch.

Explanation:

It is given that the isosceles triangle has angle measures 50°, 50°, and 80°. The side across from the 80° angle is 10 inches long.

Let the given length of other equal sides be x.

The side across from the 50° angle is x inches long.

Law of sine,

\frac{a}{\sin A}= \frac{b}{\sin B} =\frac{c}{\sin C}

\frac{x}{\sin (50)}= \frac{10}{\sin (80)}

\frac{x}{0.766} =\frac{10}{0.9848}

x =\frac{10}{0.9848}\times (0.766)

x =7.778229 \approx 7.8

Therefore, the value of other side is 7.8 inch.

3 0
4 years ago
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Reggie invests $12,000, part at 7% annual interest and part at 8.5% annual interest. how much is invested at each rate if reggie
Vika [28.1K]

Let us say that:

x = invested at 7%

y = invested at 8.5%

and that:

<span>x + y  = 12,000</span>

We can also say that:

0.07 x + 0.085 y = 900

 

Therefore:

0.07 x + 0.085 (12000 – x) = 900

0.07 x + 1020 – 0.085 x = 900

- 0.015 x = -120

x = $8000

 

so y is:

y = 12000 – 8000

y = $4,000


$8000 is invested at 7% annual interest while $4000 is invested at 8.5%

3 0
4 years ago
The hypotenuse of a right triangle measures 7 cm and one of its legs measures 5 cm. Find the measure of the other leg. If necess
blsea [12.9K]

Answer:

4.9

Step-by-step explanation:

We can use the following equation to solve

{5}^{2}  + {x}^{2}  =  {7}^{2}

Reduce

{x}^{2}  = 24

x =  \sqrt{24}

or 4.9

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Give the following equations determine if the lines are parallel perpendicular or neither
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In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

\frac{6x-5y}{2}=x+1

Cross multiply both sides of the equation.

6x-5y=2(x+1)6x-5y=2x+2

Subtract 6x on both sides of the equation.

6x-5y-6x=2x+2-6x-5y=-4x+2

Divide both sides of the equation by -5.

-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}y=\frac{4}{5}x-\frac{2}{5}

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

-4y-x=4x+5

Add x on both sides of the equation.

-4y-x+x=4x+5+x-4y=5x+5

Divide both sides of the equation by -4.

\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}y=-\frac{5}{4}x-\frac{5}{4}

Therefore, the slope of the second equation is -5/4.

Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.

5 0
2 years ago
Heather left the hospital and drove toward the desert at an average speed of 35 km/h. Danielle left sometime later driving in th
elena55 [62]

Answer:

Danielle drove 3 hours

Step-by-step explanation:

Suppose Heather moved in the x direction.

Then Danielle moved in the opposite direction, that is, she moved in the -x direction.

Let's call V_1, x_1, t_1 at the speed, distance and time that I code Heather

Let's call V_2, x_2, t_2 at the speed, distance and time Danielle codes.

Observe the following diagram:

(x) Heather <------ x_1 --------- hospital ---------- x_2 -----------> Danielle (-x)

So:

V_1 = 35\ km/h

t_1 = 4\ h

V_2 = 50\ km/h

We know that after 4 hours the distance between Heather and Danielle was 290 km.

That is to say:

x_2 + x_1 = 290\ km/h

We know that x_1= v_1t_1

x_1 = 35(4)

x_1 = 140\ km

We already know x_1, the distance from the hospital to Heather, so we can find x_2 and thus know t_2

So:

x_2 = 290 - 140\\\\x_2 = 150\ km

Then:

t_2 = \frac{x_2}{v_2}\\\\t_2 = \frac{150}{50}\\\\t_2 = 3\ h

7 0
3 years ago
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