Answer: it’s 40% if your confused… aka (A.)
Step-by-step explanation:
Answer:
91
Step-by-step explanation:
Todd’s average score for six tests = 92.
The sum of two of her test = 188
First, we need to find the total score for the six test. This given below:
Average = sum of all test / number of test
sum of all the test = average x number of test
average score for six tests = 92.
Number of test = 6
Sum of all the Tests = 92 x 6 = 552
Sum of four test = sum of all the test — sum of two test
Sum of four test = 552 — 188 = 364
Now we can solve for the average of the other four test as shown below:
Average of four test = 364/4= 91
The answer to your question would be -25/3
As decimal -8.333333
Answer:
DF = 2
Step-by-step explanation:
Formula for degree of freedom is;
DF = n - 1
Where n is sample size
In this question, political party affiliation could be Republican, Democrat, or Other. Thus, sample size is 3.
DF = 3 - 1
DF = 2
Thus, degree of freedom value would be 2
Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:

The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.
X = 82:


Z = 1
Z = 1 has a p-value of 0.84.
X = 72:


Z = 0
Z = 0 has a p-value of 0.5.
0.84 - 0.5 = 0.34.
Out of 200 students, the number is given by:
0.34 x 200 = 68 students with scores between 72 and 82.
More can be learned about the normal distribution at brainly.com/question/24663213
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