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Harrizon [31]
3 years ago
7

Suppose you are an aerospace engineer. It is your job to design a new type of fighter jet, and you have already been given a mod

el for it. The actual jet is to be 50 times as large as the model. The dimensions of the model are as follows: Length: 3 feet Width: 6 inches Height: 0.3 feet Find the dimension of the actual jet​
Mathematics
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

150 ft length 35ft width and 15ft height

Step-by-step explanation:

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An automobile insurance company divides customers into three categories: good risks, medium risks, and poor risks. Assume that o
Leokris [45]

Answer:

0.60

Step-by-step explanation:

Probability that the customer is not a poor risk = 1 - probability that the customer is a poor risk

Firstly, let’s calculate the probability of being a poor risk.

From the given data the number of poor risks = 14229-7362-1190 = 5677

So the probability of being a poor risk = 5677/14229 = 0.399

Thus, the probability that the customer is not a poor risk = 1-0.399 = 0.601 which to 2 decimal places = 0.60

6 0
3 years ago
In a simple random sample of 14001400 young​ people, 9090​% had earned a high school diploma. Complete parts a through d below.
ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has ​increased.

Step-by-step explanation:

Let <em>p</em> = proportion of young people who had earned a high school diploma.

A sample of <em>n</em> = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

\hat p=0.90

(a)

The standard error for the estimate of the percentage of all young people who earned a high school​ diploma is given by:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

Compute the standard error value as follows:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

       =\sqrt{\frac{0.90(1-0.90)}{1400}}\\

       =0.008

Thus, the standard error for the estimate of the percentage of all young people who earned a high school​ diploma is 0.0080.

(b)

The margin of error for (1 - <em>α</em>)% confidence interval for population proportion is:

MOE=z_{\alpha/2}\times SE_{\hat p}

Compute the critical value of <em>z</em> for 95% confidence level as follows:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the margin of error as follows:

MOE=z_{\alpha/2}\times SE_{\hat p}

          =1.96\times 0.0080\\=0.01568\\\approx1.6\%

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has​ increased, the hypothesis is defined as:

<em>H₀</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> = 0.80.

<em>Hₐ</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of <em>p</em>, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has ​increased.

8 0
3 years ago
HELP ME ASAP!!!!!!!!<br><br> Simplify these equations
riadik2000 [5.3K]

Step-by-step explanation:

1.3×2×a×b

=6ab

2.c5×c

=c5+1

=c6

3.2y4×5y3

=10y4+3

=10y7

4.3gh2×4g3h3

=12g1+3h2+3

=12g4h5

7 0
2 years ago
Which number is rational?
disa [49]

Answer:

I think it's A.

hope this helps

have a good day :)

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Omg help with my homework PLEASE ASAP. what donu graph and how do i suow my workkkkk whats the answer
Gnoma [55]

Answer:

you have to start with you b which in your problem is 5 so put a point at 5 on the y-axis on your graph. then with the M (the fraction numbers) you have to move either up or down depending if there is a negative number. so yours is 1/2 so then you would start at the 5 point and go up 1 and right 2 then you just keep repeating till you get a few points and can make a line then you just do the same thing for the other equation. start at 3 on the y-axis and then go up 3 and right 4 then just keep repeating till you get a few point and can create a line at the end the lines should cross each other like perpendicular lines

Step-by-step explanation:

hope this helps:)

7 0
2 years ago
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