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Svet_ta [14]
3 years ago
9

Find x. (Round final answer to the nearest tenth. Show all work.)

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

x is 12

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Y varies directly with x. When y is 105, x is 7. What is k
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3 years ago
Nicole has used 6 feet of ribbon.This represents 3/8 of the total amount of the ribbon she started with. How much ribbon did Nic
GalinKa [24]
3/8x=6. x=6*8/3. x=2*8. x=16. Nicole started with 16 feet of string.
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3 years ago
The vertices of the triangle are given. determine whether the triangle is an acute traignel, obtuse triangle
Brrunno [24]
What are the angles?

if all of them are below 90 degrees, it is acute.

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8 0
3 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
Jay traveled from Miami to Jacksonville, a distance of 320 miles. He left Miami at 8:00 AM, stopped for lunch for 30 minutes, an
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Distance Rate times Time
320= R 5.25
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