Question

What is the remainder when the polynomial f(x)=3x^3-4x^2+2x+8 is divided by (x-5)

Answer 1

Answer:

remainder = 290

Step-by-step explanation:

$\frac{3x^3-4x^2+2x+8}{x-5}$

= 3x² + 11x + 57 + $\frac{290}{x-5}$

quotient = 3x² + 11x + 57 and remainder = 290