Here's another one.
See the attached picture.
Hi there!
We can use right-triangle trigonometry to solve.
We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.
cosθ = Adjacent/Hypotenuse
We can plug in what is given:
cos(28) = A/17
Solve for 'A':
17cos(28) = <u>15.01 ft</u>
All it did was shrink in size and move to the square diagonal from it
11 x 9 is 99 so then you do 11 x d and that’s 11d so it would be 99+11d :)
6a-4 = 3a+54
3a = 58
a = 58/3
a= 19.333
