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3 years ago

What did andrew do wrong??

1 answer:

8 0

His hand slipped and she could not hold on any longer. He reached out to stop her from falling but all he caught was a single hair. She fell into the abyss and disappeared out of sight. He stared into the emptiness that had stolen his love away from him and began to cry. She was gone. He heard a faint whisper in the background that would haunt him for ever more 'Andrew, what did you do wrong?'

Sorry, I like creative writing.

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A sum of $4000 is invested at 5.5% interest per year. Find the amount of time needed to double the money if it’s compounded mont

musickatia [10]

9514 1404 393

Answer:

C) 12y 8m

Step-by-step explanation:

The amount of principal P at compound monthly at interest rate r per year is given by ...

A = P(1 +r/12)^(12t) . . . . after t years

Here, we want to find t, so ...

A/P = (1 +r/12)^(12t)

log(A/P) = (12t)·log(1 +r/12)

t = log(A/P)/(12·log(1 +r/12))

Filling in the given values, we find t to be ...

t = log(8000/4000)/(12·log(1 +0.055/12)) ≈ 12.6315 ≈ 12 years 7.6 months

It will take about 12 years 8 months to double the money.

8 0

3 years ago

Given:

lisov135 [29]

Answer:

Step-by-step explanation:

6 0

3 years ago

Which of the following is the value of f(-4) in the function f(x) = -2x - 3?<br><br> no links

Scilla [17]

Answer:

Step-by-step explanation:

f(-4)= -2(-4)-3

=8-3

8 0

3 years ago

What expressions are equivalent to q+p+q+p+q

Kipish [7]

You can resolve all of them.
so the first one would be 3q+2p
that second 2p+3q
the third 2p+2q+q which equals 2p+3q

they all end up as the same thing so both are equivalent

6 0

3 years ago

Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t

juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

$\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}$

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

6 0

3 years ago