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Elena L [17]
3 years ago
8

If a customer uses 80 MB, the monthly cost will be $19.00. If the customer uses MB, the monthly cost will be $. Find a linear eq

uation for the monthly cost of the data plan, C , as a function of x , the number of MB used. math problem
Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0

Answer:

c = 4.211\cdot n

Step-by-step explanation:

The linear equation has the following form:

c = \frac{\Delta C}{\Delta n} \cdot n

Where:

n - Number of MBs of the data plan.

c - Monthly cost of the data plan.

The slope of the function is:

\frac{\Delta C}{\Delta n} = \frac{c}{n}

\frac{\Delta C}{\Delta n} = \frac{80\,MB}{19\,USD}

\frac{\Delta C}{\Delta n} = 4.211\,\frac{MB}{USD}

The equation is:

c = 4.211\cdot n

elena-14-01-66 [18.8K]3 years ago
5 0

Full Question

If a customer uses 80 MB, the monthly cost will be $19.00. If the customer uses n MB, the monthly cost will be $C Find a linear equation for the monthly cost of the data plan, C , as a function of x , the number of MB used.

Answer:

The linear equation for the monthly cost of the data plan, C , as a function of x , the number of MB used is; C = 4.2105 n

Step-by-step explanation:

Given;

Usage = n = 80MB

Cost = ∆C = $19

Let C = monthly cost

Let x = MB per minute

The relationship between C and n is

C = ∆C * n / ∆n

C = 80/19 *n

C = 4.2105 n

The linear equation for the monthly cost of the data plan, C , as a function of x , the number of MB used is; C = 4.2105 n

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In PEMDAS, there is no parentheses in this equation, so we move on to exponents.

-5^2 is 25
Now, we divide -15/-3 then we get 5
Next, we do -3+20=17
25+5+17 would be 47

Your answer should be 47!
Hope this helps (:
5 0
3 years ago
Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
A unicycle travels 50 feet. If the radius of the tire is 24 INCHES, how many times does the tire rotate? A) about 8 times B) abo
Pie
The total distance traveled by cycle = 50 * 12 = 600 inch
1 complete rotation measures = 2 * 3.14 * 24 = 150.72 inch

Total rotation = 600 / 150.72
= approx. 4

In short, Your Answer would be Option C

Hope this helps!
6 0
3 years ago
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First multiply them all by 8
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3 years ago
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zimovet [89]

Answer:

Step-by-step explanation:

z varies inversely

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z=4/(5/4)^2

z=4/(25/16)

z=64/25

6 0
3 years ago
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