Hello,
Looking at the data, you should go with the second and fourth results.
On the second one, Dr. Appiah's M.A.D. is only 9.7 which is less than Dr. Singh's M.A.D. of 14.1
On the fourth one, Dr. Cantwell and Dr. Singh both have a M.A.D. that is only 0.1 from 14, so their ages vary by about the same amount.
Best of luck,
MrEQ
Answer:
Your measurements; Area = 216.108 cm²
Another student's measurements; Area = 216.9404 cm²
- Difference in area could be as a result of human error or perhaps that they made use of different measuring tools.
Step-by-step explanation:
For Your measurements;
Length of rectangle = 20.70 cm
Width of rectangle = 10.44 cm
Area of rectangle is given by; A = length × width = 20.7 × 10.44 = 216.108 cm²
For Another student's measurements;
Length of rectangle = 20.74 cm
Width of rectangle = 10.46 cm
Area = 20.74 × 10.46
Area = 216.9404 cm²
The areas they both obtained are not of equal values and this could be as a result of human error or perhaps that they used different measuring tools.
Answer:
the answer is 0.24 jjjjjjjjjjjjjj
Answer:
0.38268343
Step-by-step explanation:
cos(
67.5
)
Rewrite
67.5
as an angle where the values of the six trigonometric functions are known divided by 2
.
cos
(
135\
2)
Apply the cosine half-angle identity.
±
√
1
+
cos
(
135
)
2
Change the
±
to
+
because cosine is positive in the first quadrant.
√
1
+
cos
(
135
)
2
Simplify
√
1
+
cos
(
135
)
2
√
2
−
√
2
2
The result can be shown in multiple forms.
Exact Form:
√
2
−
√
2
2
Decimal Form:
0.38268343
…
We are given a right triangle and we are asked to determine the hypotenuse given the measure of its sides. To do that we will use the Pythagorean theorem:
Now, we solve the square:
Now, we add the values:
Now, we take the square root to both sides:
![h=\sqrt[]{500km^2}](https://tex.z-dn.net/?f=h%3D%5Csqrt%5B%5D%7B500km%5E2%7D)
Solving the operations:
Therefore, the length of the hypotenuse is 22.361 kilometers.
