Answer:
26π
Step-by-step explanation:
Hmm... This one is a little hard to understand because of the LaTeX.
Any way, way back to the question. A useful piece of information:
<u>The formula for finding the circumference of a circle is 2πr or π · d :</u>
We first need to find out what x is.
Since 2 times the radius is the diameter, we can set up our equation like this:
2(x + 6) = 3x + 5
Solving gives:
2x + 12 = 3x + 5.
We subtract 2x from both sides:
+12 = x + 5
Subtract 5:
So x = 7.
Now we can plug-and-chug:
7 + 6 = 13 times 2pi (this is the radius)
21 + 5 = 26 times pi.
<u>Check:</u>
When we check 13 (radius) times 2 should equal the diameter(26)
13 * 2 = 26.
So we are correct. The answer 26π is correct.
Zero's:9
Turning point:3,8
Y-intercept:2,5
Axis of sym,etry::X-axis
Step-by-step explanation:Let number of 49 cents =A
Let number of 33 cents=B
<u>A+B=45 equation 1</u>
1 $=100 cents
49 cents =.49 dollar
33 cents=.33 dollar
so .<u>49A+.33B=17.89 equation 2</u>
Add equation 1 and equation 2
since these are simultaneous equations
.49A+.33B=17.89
A+ B=45
so divide equation 2 by 100 we get
49A+33B=1789
A+B =45 multiply equation 1 by 33 on both the sides we get
<u>33A+33B=1485 equation 3</u>
so subtract equation 3 from equation 2 we get
49A+33B=1789 equation 2
<u>33A+33B=1485 equation 3</u>
<u>16A+0 =304</u>
16A=304
A=304/16
A=19
putting nalue of A in equation 1 we get
A+B=45
19+B=45
B=45-19
B=26
so number of 49 cent stamps are 19
and number of 33 cent stamps are 26
Answer:
3 and 4 are factors of 12 so they should be multiplied to get a product of 12 ab. (Answer D)
Step-by-step explanation:
You do not multiply in addition unless an exponent is present. You should not multiply or add considering these are not like terms. Therefore, D is wrong.
The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:
Mean score of A = (sum of all scores) / 15
55 = (sum of all scores) / 15
sum of all scores in A = 825
The mean score for both classes is 76. Hence:
[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes
[825 + (sum of all scores in B)]/(15 + 29) = 76
sum of all scores in B = 2519
Mean score of B = (2519) / 29 = 86.86
The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.
Find out more on equation at: brainly.com/question/13763238
#SPJ1
