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2 years ago

14

Based on the scatter plot, is there any positive, negative or no correlation? Explain

1 answer:

mixer [17]2 years ago

6 0

Answer:

A scatter plot is a type of graph that shows pairs of data plotted as points. ... If the points on the scatter plot seem to be scattered randomly, there is no relationship or no correlation between the variables. When there is a positive or negative relationship between your variables, you can draw a line of best fit.

-hope that helps! =)

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The line plot shows the length of rope (in feet) of five pieces of rope. What is the difference in length between the longest an

Vikki [24]

Answer: am sorry G i can't get that answers for you

Step-by-step explanation:

8 0

2 years ago

1 tenth is how many times greater than 1 hundredth

Anna35 [415]

Answer:

10

Step-by-step explanation:

1 tenth: 1/10

1 hundredth: 1/100

1/10 = X × 1/100

X = 100/10

X = 10

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3 years ago

Read 2 more answers

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

b.

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

c.

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

Read 2 more answers

What’s the correct answer

ale4655 [162]

$45x=11\qquad\text{divide both sides by 45}\\\\\boxed{x=\dfrac{11}{45}}=0.2\overline{4}\\\\Answer:\ \boxed{x\approx0.24}$

7 0

3 years ago

Hello, can anyone help please? :D

Lubov Fominskaja [6]

Answer:

just guess

Step-by-step explanation:

i got it right

6 0

2 years ago